Metamath Proof Explorer


Theorem symgmatr01

Description: Applying a permutation that does not fix a certain element of a set to a second element to an index of a matrix a row with 0's and a 1. (Contributed by AV, 3-Jan-2019)

Ref Expression
Hypotheses symgmatr01.p ⊢ P = Base SymGrp ⁡ N
symgmatr01.0 ⊢ 0 ˙ = 0 R
symgmatr01.1 ⊢ 1 ˙ = 1 R
Assertion symgmatr01 ⊢ K ∈ N ∧ L ∈ N → Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = 0 ˙

Proof

Step Hyp Ref Expression
1 symgmatr01.p ⊢ P = Base SymGrp ⁡ N
2 symgmatr01.0 ⊢ 0 ˙ = 0 R
3 symgmatr01.1 ⊢ 1 ˙ = 1 R
4 1 symgmatr01lem ⊢ K ∈ N ∧ L ∈ N → Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k = 0 ˙
5 4 imp ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k = 0 ˙
6 eqidd ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j = i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j
7 eqeq1 ⊢ i = k → i = K ↔ k = K
8 7 adantr ⊢ i = k ∧ j = Q ⁡ k → i = K ↔ k = K
9 eqeq1 ⊢ j = Q ⁡ k → j = L ↔ Q ⁡ k = L
10 9 adantl ⊢ i = k ∧ j = Q ⁡ k → j = L ↔ Q ⁡ k = L
11 10 ifbid ⊢ i = k ∧ j = Q ⁡ k → if j = L 1 ˙ 0 ˙ = if Q ⁡ k = L 1 ˙ 0 ˙
12 oveq12 ⊢ i = k ∧ j = Q ⁡ k → i M j = k M Q ⁡ k
13 8 11 12 ifbieq12d ⊢ i = k ∧ j = Q ⁡ k → if i = K if j = L 1 ˙ 0 ˙ i M j = if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k
14 13 adantl ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N ∧ i = k ∧ j = Q ⁡ k → if i = K if j = L 1 ˙ 0 ˙ i M j = if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k
15 simpr ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → k ∈ N
16 eldifi ⊢ Q ∈ P ∖ q ∈ P | q ⁡ K = L → Q ∈ P
17 eqid ⊢ SymGrp ⁡ N = SymGrp ⁡ N
18 17 1 symgfv ⊢ Q ∈ P ∧ k ∈ N → Q ⁡ k ∈ N
19 18 ex ⊢ Q ∈ P → k ∈ N → Q ⁡ k ∈ N
20 16 19 syl ⊢ Q ∈ P ∖ q ∈ P | q ⁡ K = L → k ∈ N → Q ⁡ k ∈ N
21 20 adantl ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L → k ∈ N → Q ⁡ k ∈ N
22 21 imp ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → Q ⁡ k ∈ N
23 3 fvexi ⊢ 1 ˙ ∈ V
24 2 fvexi ⊢ 0 ˙ ∈ V
25 23 24 ifex ⊢ if Q ⁡ k = L 1 ˙ 0 ˙ ∈ V
26 ovex ⊢ k M Q ⁡ k ∈ V
27 25 26 ifex ⊢ if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k ∈ V
28 27 a1i ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k ∈ V
29 6 14 15 22 28 ovmpod ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k
30 29 eqeq1d ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L ∧ k ∈ N → k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = 0 ˙ ↔ if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k = 0 ˙
31 30 rexbidva ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = 0 ˙ ↔ ∃ k ∈ N if k = K if Q ⁡ k = L 1 ˙ 0 ˙ k M Q ⁡ k = 0 ˙
32 5 31 mpbird ⊢ K ∈ N ∧ L ∈ N ∧ Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = 0 ˙
33 32 ex ⊢ K ∈ N ∧ L ∈ N → Q ∈ P ∖ q ∈ P | q ⁡ K = L → ∃ k ∈ N k i ∈ N , j ∈ N ⟼ if i = K if j = L 1 ˙ 0 ˙ i M j Q ⁡ k = 0 ˙