Metamath Proof Explorer


Theorem tcss

Description: The transitive closure function inherits the subset relation. (Contributed by Mario Carneiro, 23-Jun-2013)

Ref Expression
Hypothesis tc2.1 ⊢ A ∈ V
Assertion tcss ⊢ B ⊆ A → TC ⁡ B ⊆ TC ⁡ A

Proof

Step Hyp Ref Expression
1 tc2.1 ⊢ A ∈ V
2 1 ssex ⊢ B ⊆ A → B ∈ V
3 tcvalg ⊢ B ∈ V → TC ⁡ B = ⋂ x | B ⊆ x ∧ Tr ⁡ x
4 2 3 syl ⊢ B ⊆ A → TC ⁡ B = ⋂ x | B ⊆ x ∧ Tr ⁡ x
5 sstr2 ⊢ B ⊆ A → A ⊆ x → B ⊆ x
6 5 anim1d ⊢ B ⊆ A → A ⊆ x ∧ Tr ⁡ x → B ⊆ x ∧ Tr ⁡ x
7 6 ss2abdv ⊢ B ⊆ A → x | A ⊆ x ∧ Tr ⁡ x ⊆ x | B ⊆ x ∧ Tr ⁡ x
8 intss ⊢ x | A ⊆ x ∧ Tr ⁡ x ⊆ x | B ⊆ x ∧ Tr ⁡ x → ⋂ x | B ⊆ x ∧ Tr ⁡ x ⊆ ⋂ x | A ⊆ x ∧ Tr ⁡ x
9 7 8 syl ⊢ B ⊆ A → ⋂ x | B ⊆ x ∧ Tr ⁡ x ⊆ ⋂ x | A ⊆ x ∧ Tr ⁡ x
10 tcvalg ⊢ A ∈ V → TC ⁡ A = ⋂ x | A ⊆ x ∧ Tr ⁡ x
11 1 10 ax-mp ⊢ TC ⁡ A = ⋂ x | A ⊆ x ∧ Tr ⁡ x
12 9 11 sseqtrrdi ⊢ B ⊆ A → ⋂ x | B ⊆ x ∧ Tr ⁡ x ⊆ TC ⁡ A
13 4 12 eqsstrd ⊢ B ⊆ A → TC ⁡ B ⊆ TC ⁡ A