Metamath Proof Explorer


Theorem tendocan

Description: Cancellation law: if the values of two trace-preserving endormorphisms are equal, so are the endormorphisms. Lemma J of Crawley p. 118. (Contributed by NM, 21-Jun-2013)

Ref Expression
Hypotheses tendocan.b ⊢ B = Base K
tendocan.h ⊢ H = LHyp ⁡ K
tendocan.t ⊢ T = LTrn ⁡ K ⁡ W
tendocan.e ⊢ E = TEndo ⁡ K ⁡ W
Assertion tendocan ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → U = V

Proof

Step Hyp Ref Expression
1 tendocan.b ⊢ B = Base K
2 tendocan.h ⊢ H = LHyp ⁡ K
3 tendocan.t ⊢ T = LTrn ⁡ K ⁡ W
4 tendocan.e ⊢ E = TEndo ⁡ K ⁡ W
5 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → K ∈ HL
6 simp1r ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → W ∈ H
7 simp21 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → U ∈ E
8 simp22 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → V ∈ E
9 simp11 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → K ∈ HL ∧ W ∈ H
10 simp12 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F
11 simp13l ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → F ∈ T
12 simp13r ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → F ≠ I ↾ B
13 simp2 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → h ∈ T
14 11 12 13 3jca ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T
15 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → h ≠ I ↾ B
16 eqid ⊢ trL ⁡ K ⁡ W = trL ⁡ K ⁡ W
17 1 2 3 16 4 cdlemj3 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → U ⁡ h = V ⁡ h
18 9 10 14 15 17 syl31anc ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B ∧ h ∈ T ∧ h ≠ I ↾ B → U ⁡ h = V ⁡ h
19 18 3exp ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → h ∈ T → h ≠ I ↾ B → U ⁡ h = V ⁡ h
20 19 ralrimiv ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → ∀ h ∈ T h ≠ I ↾ B → U ⁡ h = V ⁡ h
21 1 2 3 4 tendoeq2 ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ ∀ h ∈ T h ≠ I ↾ B → U ⁡ h = V ⁡ h → U = V
22 5 6 7 8 20 21 syl221anc ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E ∧ V ∈ E ∧ U ⁡ F = V ⁡ F ∧ F ∈ T ∧ F ≠ I ↾ B → U = V