Metamath Proof Explorer


Theorem tgbtwnconn1lem2

Description: Lemma for tgbtwnconn1 . (Contributed by Thierry Arnoux, 30-Apr-2019)

Ref Expression
Hypotheses tgbtwnconn1.p ⊢ P = Base G
tgbtwnconn1.i ⊢ I = Itv ⁡ G
tgbtwnconn1.g ⊢ φ → G ∈ 𝒢 Tarski
tgbtwnconn1.a ⊢ φ → A ∈ P
tgbtwnconn1.b ⊢ φ → B ∈ P
tgbtwnconn1.c ⊢ φ → C ∈ P
tgbtwnconn1.d ⊢ φ → D ∈ P
tgbtwnconn1.1 ⊢ φ → A ≠ B
tgbtwnconn1.2 ⊢ φ → B ∈ A I C
tgbtwnconn1.3 ⊢ φ → B ∈ A I D
tgbtwnconn1.m ⊢ - ˙ = dist ⁡ G
tgbtwnconn1.e ⊢ φ → E ∈ P
tgbtwnconn1.f ⊢ φ → F ∈ P
tgbtwnconn1.h ⊢ φ → H ∈ P
tgbtwnconn1.j ⊢ φ → J ∈ P
tgbtwnconn1.4 ⊢ φ → D ∈ A I E
tgbtwnconn1.5 ⊢ φ → C ∈ A I F
tgbtwnconn1.6 ⊢ φ → E ∈ A I H
tgbtwnconn1.7 ⊢ φ → F ∈ A I J
tgbtwnconn1.8 ⊢ φ → E - ˙ D = C - ˙ D
tgbtwnconn1.9 ⊢ φ → C - ˙ F = C - ˙ D
tgbtwnconn1.10 ⊢ φ → E - ˙ H = B - ˙ C
tgbtwnconn1.11 ⊢ φ → F - ˙ J = B - ˙ D
Assertion tgbtwnconn1lem2 ⊢ φ → E - ˙ F = C - ˙ D

Proof

Step Hyp Ref Expression
1 tgbtwnconn1.p ⊢ P = Base G
2 tgbtwnconn1.i ⊢ I = Itv ⁡ G
3 tgbtwnconn1.g ⊢ φ → G ∈ 𝒢 Tarski
4 tgbtwnconn1.a ⊢ φ → A ∈ P
5 tgbtwnconn1.b ⊢ φ → B ∈ P
6 tgbtwnconn1.c ⊢ φ → C ∈ P
7 tgbtwnconn1.d ⊢ φ → D ∈ P
8 tgbtwnconn1.1 ⊢ φ → A ≠ B
9 tgbtwnconn1.2 ⊢ φ → B ∈ A I C
10 tgbtwnconn1.3 ⊢ φ → B ∈ A I D
11 tgbtwnconn1.m ⊢ - ˙ = dist ⁡ G
12 tgbtwnconn1.e ⊢ φ → E ∈ P
13 tgbtwnconn1.f ⊢ φ → F ∈ P
14 tgbtwnconn1.h ⊢ φ → H ∈ P
15 tgbtwnconn1.j ⊢ φ → J ∈ P
16 tgbtwnconn1.4 ⊢ φ → D ∈ A I E
17 tgbtwnconn1.5 ⊢ φ → C ∈ A I F
18 tgbtwnconn1.6 ⊢ φ → E ∈ A I H
19 tgbtwnconn1.7 ⊢ φ → F ∈ A I J
20 tgbtwnconn1.8 ⊢ φ → E - ˙ D = C - ˙ D
21 tgbtwnconn1.9 ⊢ φ → C - ˙ F = C - ˙ D
22 tgbtwnconn1.10 ⊢ φ → E - ˙ H = B - ˙ C
23 tgbtwnconn1.11 ⊢ φ → F - ˙ J = B - ˙ D
24 1 11 2 3 12 13 axtgcgrrflx ⊢ φ → E - ˙ F = F - ˙ E
25 24 adantr ⊢ φ ∧ B = C → E - ˙ F = F - ˙ E
26 3 adantr ⊢ φ ∧ B = C → G ∈ 𝒢 Tarski
27 12 adantr ⊢ φ ∧ B = C → E ∈ P
28 14 adantr ⊢ φ ∧ B = C → H ∈ P
29 6 adantr ⊢ φ ∧ B = C → C ∈ P
30 22 adantr ⊢ φ ∧ B = C → E - ˙ H = B - ˙ C
31 simpr ⊢ φ ∧ B = C → B = C
32 31 oveq1d ⊢ φ ∧ B = C → B - ˙ C = C - ˙ C
33 30 32 eqtrd ⊢ φ ∧ B = C → E - ˙ H = C - ˙ C
34 1 11 2 26 27 28 29 33 axtgcgrid ⊢ φ ∧ B = C → E = H
35 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 tgbtwnconn1lem1 ⊢ φ → H = J
36 35 adantr ⊢ φ ∧ B = C → H = J
37 34 36 eqtrd ⊢ φ ∧ B = C → E = J
38 37 oveq2d ⊢ φ ∧ B = C → F - ˙ E = F - ˙ J
39 23 adantr ⊢ φ ∧ B = C → F - ˙ J = B - ˙ D
40 31 oveq1d ⊢ φ ∧ B = C → B - ˙ D = C - ˙ D
41 38 39 40 3eqtrd ⊢ φ ∧ B = C → F - ˙ E = C - ˙ D
42 25 41 eqtrd ⊢ φ ∧ B = C → E - ˙ F = C - ˙ D
43 3 adantr ⊢ φ ∧ B ≠ C → G ∈ 𝒢 Tarski
44 13 adantr ⊢ φ ∧ B ≠ C → F ∈ P
45 12 adantr ⊢ φ ∧ B ≠ C → E ∈ P
46 7 adantr ⊢ φ ∧ B ≠ C → D ∈ P
47 6 adantr ⊢ φ ∧ B ≠ C → C ∈ P
48 5 adantr ⊢ φ ∧ B ≠ C → B ∈ P
49 15 adantr ⊢ φ ∧ B ≠ C → J ∈ P
50 simpr ⊢ φ ∧ B ≠ C → B ≠ C
51 1 11 2 3 4 5 6 13 9 17 tgbtwnexch3 ⊢ φ → C ∈ B I F
52 51 adantr ⊢ φ ∧ B ≠ C → C ∈ B I F
53 35 oveq2d ⊢ φ → A I H = A I J
54 18 53 eleqtrd ⊢ φ → E ∈ A I J
55 1 11 2 3 4 7 12 15 16 54 tgbtwnexch3 ⊢ φ → E ∈ D I J
56 1 11 2 3 7 12 15 55 tgbtwncom ⊢ φ → E ∈ J I D
57 56 adantr ⊢ φ ∧ B ≠ C → E ∈ J I D
58 35 adantr ⊢ φ ∧ B ≠ C → H = J
59 58 oveq2d ⊢ φ ∧ B ≠ C → E - ˙ H = E - ˙ J
60 22 adantr ⊢ φ ∧ B ≠ C → E - ˙ H = B - ˙ C
61 1 11 2 43 45 49 axtgcgrrflx ⊢ φ ∧ B ≠ C → E - ˙ J = J - ˙ E
62 59 60 61 3eqtr3d ⊢ φ ∧ B ≠ C → B - ˙ C = J - ˙ E
63 21 20 eqtr4d ⊢ φ → C - ˙ F = E - ˙ D
64 63 adantr ⊢ φ ∧ B ≠ C → C - ˙ F = E - ˙ D
65 1 11 2 3 4 5 7 12 10 16 tgbtwnexch3 ⊢ φ → D ∈ B I E
66 65 adantr ⊢ φ ∧ B ≠ C → D ∈ B I E
67 1 11 2 3 4 6 13 15 17 19 tgbtwnexch3 ⊢ φ → F ∈ C I J
68 1 11 2 3 6 13 15 67 tgbtwncom ⊢ φ → F ∈ J I C
69 68 adantr ⊢ φ ∧ B ≠ C → F ∈ J I C
70 1 11 2 3 15 13 axtgcgrrflx ⊢ φ → J - ˙ F = F - ˙ J
71 70 23 eqtr2d ⊢ φ → B - ˙ D = J - ˙ F
72 71 adantr ⊢ φ ∧ B ≠ C → B - ˙ D = J - ˙ F
73 1 11 2 3 6 13 12 7 63 tgcgrcomlr ⊢ φ → F - ˙ C = D - ˙ E
74 73 adantr ⊢ φ ∧ B ≠ C → F - ˙ C = D - ˙ E
75 74 eqcomd ⊢ φ ∧ B ≠ C → D - ˙ E = F - ˙ C
76 1 11 2 43 48 46 45 49 44 47 66 69 72 75 tgcgrextend ⊢ φ ∧ B ≠ C → B - ˙ E = J - ˙ C
77 1 11 2 43 47 45 axtgcgrrflx ⊢ φ ∧ B ≠ C → C - ˙ E = E - ˙ C
78 1 11 2 43 48 47 44 49 45 46 45 47 50 52 57 62 64 76 77 axtg5seg ⊢ φ ∧ B ≠ C → F - ˙ E = D - ˙ C
79 1 11 2 43 44 45 46 47 78 tgcgrcomlr ⊢ φ ∧ B ≠ C → E - ˙ F = C - ˙ D
80 42 79 pm2.61dane ⊢ φ → E - ˙ F = C - ˙ D