Metamath Proof Explorer


Theorem tgcgreq

Description: Congruence and equality. (Contributed by Thierry Arnoux, 27-Aug-2019)

Ref Expression
Hypotheses tkgeom.p ⊢ P = Base G
tkgeom.d ⊢ - ˙ = dist ⁡ G
tkgeom.i ⊢ I = Itv ⁡ G
tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
tgcgrcomlr.a ⊢ φ → A ∈ P
tgcgrcomlr.b ⊢ φ → B ∈ P
tgcgrcomlr.c ⊢ φ → C ∈ P
tgcgrcomlr.d ⊢ φ → D ∈ P
tgcgrcomlr.6 ⊢ φ → A - ˙ B = C - ˙ D
tgcgreq.1 ⊢ φ → A = B
Assertion tgcgreq ⊢ φ → C = D

Proof

Step Hyp Ref Expression
1 tkgeom.p ⊢ P = Base G
2 tkgeom.d ⊢ - ˙ = dist ⁡ G
3 tkgeom.i ⊢ I = Itv ⁡ G
4 tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
5 tgcgrcomlr.a ⊢ φ → A ∈ P
6 tgcgrcomlr.b ⊢ φ → B ∈ P
7 tgcgrcomlr.c ⊢ φ → C ∈ P
8 tgcgrcomlr.d ⊢ φ → D ∈ P
9 tgcgrcomlr.6 ⊢ φ → A - ˙ B = C - ˙ D
10 tgcgreq.1 ⊢ φ → A = B
11 1 2 3 4 5 6 7 8 9 tgcgreqb ⊢ φ → A = B ↔ C = D
12 10 11 mpbid ⊢ φ → C = D