Metamath Proof Explorer


Theorem tgcgreqb

Description: Congruence and equality. (Contributed by Thierry Arnoux, 27-Aug-2019)

Ref Expression
Hypotheses tkgeom.p ⊢ P = Base G
tkgeom.d ⊢ - ˙ = dist ⁡ G
tkgeom.i ⊢ I = Itv ⁡ G
tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
tgcgrcomlr.a ⊢ φ → A ∈ P
tgcgrcomlr.b ⊢ φ → B ∈ P
tgcgrcomlr.c ⊢ φ → C ∈ P
tgcgrcomlr.d ⊢ φ → D ∈ P
tgcgrcomlr.6 ⊢ φ → A - ˙ B = C - ˙ D
Assertion tgcgreqb ⊢ φ → A = B ↔ C = D

Proof

Step Hyp Ref Expression
1 tkgeom.p ⊢ P = Base G
2 tkgeom.d ⊢ - ˙ = dist ⁡ G
3 tkgeom.i ⊢ I = Itv ⁡ G
4 tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
5 tgcgrcomlr.a ⊢ φ → A ∈ P
6 tgcgrcomlr.b ⊢ φ → B ∈ P
7 tgcgrcomlr.c ⊢ φ → C ∈ P
8 tgcgrcomlr.d ⊢ φ → D ∈ P
9 tgcgrcomlr.6 ⊢ φ → A - ˙ B = C - ˙ D
10 4 adantr ⊢ φ ∧ A = B → G ∈ 𝒢 Tarski
11 7 adantr ⊢ φ ∧ A = B → C ∈ P
12 8 adantr ⊢ φ ∧ A = B → D ∈ P
13 6 adantr ⊢ φ ∧ A = B → B ∈ P
14 9 adantr ⊢ φ ∧ A = B → A - ˙ B = C - ˙ D
15 simpr ⊢ φ ∧ A = B → A = B
16 15 oveq1d ⊢ φ ∧ A = B → A - ˙ B = B - ˙ B
17 14 16 eqtr3d ⊢ φ ∧ A = B → C - ˙ D = B - ˙ B
18 1 2 3 10 11 12 13 17 axtgcgrid ⊢ φ ∧ A = B → C = D
19 4 adantr ⊢ φ ∧ C = D → G ∈ 𝒢 Tarski
20 5 adantr ⊢ φ ∧ C = D → A ∈ P
21 6 adantr ⊢ φ ∧ C = D → B ∈ P
22 8 adantr ⊢ φ ∧ C = D → D ∈ P
23 9 adantr ⊢ φ ∧ C = D → A - ˙ B = C - ˙ D
24 simpr ⊢ φ ∧ C = D → C = D
25 24 oveq1d ⊢ φ ∧ C = D → C - ˙ D = D - ˙ D
26 23 25 eqtrd ⊢ φ ∧ C = D → A - ˙ B = D - ˙ D
27 1 2 3 19 20 21 22 26 axtgcgrid ⊢ φ ∧ C = D → A = B
28 18 27 impbida ⊢ φ → A = B ↔ C = D