Metamath Proof Explorer


Theorem tghilberti1

Description: There is a line through any two distinct points. Hilbert's axiom I.1 for geometry. (Contributed by Thierry Arnoux, 25-May-2019)

Ref Expression
Hypotheses tglineelsb2.p ⊢ B = Base G
tglineelsb2.i ⊢ I = Itv ⁡ G
tglineelsb2.l ⊢ L = Line 𝒢 ⁡ G
tglineelsb2.g ⊢ φ → G ∈ 𝒢 Tarski
tglineelsb2.1 ⊢ φ → P ∈ B
tglineelsb2.2 ⊢ φ → Q ∈ B
tglineelsb2.4 ⊢ φ → P ≠ Q
Assertion tghilberti1 ⊢ φ → ∃ x ∈ ran ⁡ L P ∈ x ∧ Q ∈ x

Proof

Step Hyp Ref Expression
1 tglineelsb2.p ⊢ B = Base G
2 tglineelsb2.i ⊢ I = Itv ⁡ G
3 tglineelsb2.l ⊢ L = Line 𝒢 ⁡ G
4 tglineelsb2.g ⊢ φ → G ∈ 𝒢 Tarski
5 tglineelsb2.1 ⊢ φ → P ∈ B
6 tglineelsb2.2 ⊢ φ → Q ∈ B
7 tglineelsb2.4 ⊢ φ → P ≠ Q
8 1 2 3 4 5 6 7 tgelrnln ⊢ φ → P L Q ∈ ran ⁡ L
9 1 2 3 4 5 6 7 tglinerflx1 ⊢ φ → P ∈ P L Q
10 1 2 3 4 5 6 7 tglinerflx2 ⊢ φ → Q ∈ P L Q
11 eleq2 ⊢ x = P L Q → P ∈ x ↔ P ∈ P L Q
12 eleq2 ⊢ x = P L Q → Q ∈ x ↔ Q ∈ P L Q
13 11 12 anbi12d ⊢ x = P L Q → P ∈ x ∧ Q ∈ x ↔ P ∈ P L Q ∧ Q ∈ P L Q
14 13 rspcev ⊢ P L Q ∈ ran ⁡ L ∧ P ∈ P L Q ∧ Q ∈ P L Q → ∃ x ∈ ran ⁡ L P ∈ x ∧ Q ∈ x
15 8 9 10 14 syl12anc ⊢ φ → ∃ x ∈ ran ⁡ L P ∈ x ∧ Q ∈ x