Metamath Proof Explorer


Theorem tglineelsb2

Description: If S lies on PQ , then PQ = PS . Theorem 6.16 of Schwabhauser p. 45. (Contributed by Thierry Arnoux, 17-May-2019)

Ref Expression
Hypotheses tglineelsb2.p ⊢ B = Base G
tglineelsb2.i ⊢ I = Itv ⁡ G
tglineelsb2.l ⊢ L = Line 𝒢 ⁡ G
tglineelsb2.g ⊢ φ → G ∈ 𝒢 Tarski
tglineelsb2.1 ⊢ φ → P ∈ B
tglineelsb2.2 ⊢ φ → Q ∈ B
tglineelsb2.4 ⊢ φ → P ≠ Q
tglineelsb2.3 ⊢ φ → S ∈ B
tglineelsb2.5 ⊢ φ → S ≠ P
tglineelsb2.6 ⊢ φ → S ∈ P L Q
Assertion tglineelsb2 ⊢ φ → P L Q = P L S

Proof

Step Hyp Ref Expression
1 tglineelsb2.p ⊢ B = Base G
2 tglineelsb2.i ⊢ I = Itv ⁡ G
3 tglineelsb2.l ⊢ L = Line 𝒢 ⁡ G
4 tglineelsb2.g ⊢ φ → G ∈ 𝒢 Tarski
5 tglineelsb2.1 ⊢ φ → P ∈ B
6 tglineelsb2.2 ⊢ φ → Q ∈ B
7 tglineelsb2.4 ⊢ φ → P ≠ Q
8 tglineelsb2.3 ⊢ φ → S ∈ B
9 tglineelsb2.5 ⊢ φ → S ≠ P
10 tglineelsb2.6 ⊢ φ → S ∈ P L Q
11 4 adantr ⊢ φ ∧ x ∈ P L Q → G ∈ 𝒢 Tarski
12 5 adantr ⊢ φ ∧ x ∈ P L Q → P ∈ B
13 8 adantr ⊢ φ ∧ x ∈ P L Q → S ∈ B
14 9 necomd ⊢ φ → P ≠ S
15 14 adantr ⊢ φ ∧ x ∈ P L Q → P ≠ S
16 6 adantr ⊢ φ ∧ x ∈ P L Q → Q ∈ B
17 7 necomd ⊢ φ → Q ≠ P
18 17 adantr ⊢ φ ∧ x ∈ P L Q → Q ≠ P
19 10 adantr ⊢ φ ∧ x ∈ P L Q → S ∈ P L Q
20 1 2 3 11 16 12 13 18 19 lncom ⊢ φ ∧ x ∈ P L Q → S ∈ Q L P
21 1 2 3 11 12 13 16 15 20 18 lnrot1 ⊢ φ ∧ x ∈ P L Q → Q ∈ P L S
22 1 3 2 4 5 6 7 tglnssp ⊢ φ → P L Q ⊆ B
23 22 sselda ⊢ φ ∧ x ∈ P L Q → x ∈ B
24 simpr ⊢ φ ∧ x ∈ P L Q → x ∈ P L Q
25 1 2 3 11 12 13 15 16 18 21 23 24 tglineeltr ⊢ φ ∧ x ∈ P L Q → x ∈ P L S
26 4 adantr ⊢ φ ∧ x ∈ P L S → G ∈ 𝒢 Tarski
27 5 adantr ⊢ φ ∧ x ∈ P L S → P ∈ B
28 6 adantr ⊢ φ ∧ x ∈ P L S → Q ∈ B
29 7 adantr ⊢ φ ∧ x ∈ P L S → P ≠ Q
30 8 adantr ⊢ φ ∧ x ∈ P L S → S ∈ B
31 9 adantr ⊢ φ ∧ x ∈ P L S → S ≠ P
32 10 adantr ⊢ φ ∧ x ∈ P L S → S ∈ P L Q
33 1 3 2 4 5 8 14 tglnssp ⊢ φ → P L S ⊆ B
34 33 sselda ⊢ φ ∧ x ∈ P L S → x ∈ B
35 simpr ⊢ φ ∧ x ∈ P L S → x ∈ P L S
36 1 2 3 26 27 28 29 30 31 32 34 35 tglineeltr ⊢ φ ∧ x ∈ P L S → x ∈ P L Q
37 25 36 impbida ⊢ φ → x ∈ P L Q ↔ x ∈ P L S
38 37 eqrdv ⊢ φ → P L Q = P L S