Metamath Proof Explorer


Theorem toplatglb0

Description: The empty intersection in a topology is realized by the base set. (Contributed by Zhi Wang, 30-Sep-2024)

Ref Expression
Hypotheses topclat.i ⊢ I = toInc ⁡ J
toplatlub.j ⊢ φ → J ∈ Top
toplatglb0.g ⊢ G = glb ⁡ I
Assertion toplatglb0 ⊢ φ → G ⁡ ∅ = ⋃ J

Proof

Step Hyp Ref Expression
1 topclat.i ⊢ I = toInc ⁡ J
2 toplatlub.j ⊢ φ → J ∈ Top
3 toplatglb0.g ⊢ G = glb ⁡ I
4 3 a1i ⊢ φ → G = glb ⁡ I
5 eqid ⊢ ⋃ J = ⋃ J
6 5 topopn ⊢ J ∈ Top → ⋃ J ∈ J
7 2 6 syl ⊢ φ → ⋃ J ∈ J
8 1 4 7 ipoglb0 ⊢ φ → G ⁡ ∅ = ⋃ J