Metamath Proof Explorer


Theorem tposeqd

Description: Equality theorem for transposition. (Contributed by Mario Carneiro, 7-Jan-2017)

Ref Expression
Hypothesis tposeqd.1 ⊢ φ → F = G
Assertion tposeqd ⊢ φ → tpos F = tpos G

Proof

Step Hyp Ref Expression
1 tposeqd.1 ⊢ φ → F = G
2 tposeq ⊢ F = G → tpos F = tpos G
3 1 2 syl ⊢ φ → tpos F = tpos G