Metamath Proof Explorer


Theorem trgcgr

Description: Triangle congruence. (Contributed by Thierry Arnoux, 27-Apr-2019)

Ref Expression
Hypotheses trgcgrg.p ⊢ P = Base G
trgcgrg.m ⊢ - ˙ = dist ⁡ G
trgcgrg.r ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
trgcgrg.g ⊢ φ → G ∈ 𝒢 Tarski
trgcgrg.a ⊢ φ → A ∈ P
trgcgrg.b ⊢ φ → B ∈ P
trgcgrg.c ⊢ φ → C ∈ P
trgcgrg.d ⊢ φ → D ∈ P
trgcgrg.e ⊢ φ → E ∈ P
trgcgrg.f ⊢ φ → F ∈ P
trgcgr.1 ⊢ φ → A - ˙ B = D - ˙ E
trgcgr.2 ⊢ φ → B - ˙ C = E - ˙ F
trgcgr.3 ⊢ φ → C - ˙ A = F - ˙ D
Assertion trgcgr ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩

Proof

Step Hyp Ref Expression
1 trgcgrg.p ⊢ P = Base G
2 trgcgrg.m ⊢ - ˙ = dist ⁡ G
3 trgcgrg.r ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
4 trgcgrg.g ⊢ φ → G ∈ 𝒢 Tarski
5 trgcgrg.a ⊢ φ → A ∈ P
6 trgcgrg.b ⊢ φ → B ∈ P
7 trgcgrg.c ⊢ φ → C ∈ P
8 trgcgrg.d ⊢ φ → D ∈ P
9 trgcgrg.e ⊢ φ → E ∈ P
10 trgcgrg.f ⊢ φ → F ∈ P
11 trgcgr.1 ⊢ φ → A - ˙ B = D - ˙ E
12 trgcgr.2 ⊢ φ → B - ˙ C = E - ˙ F
13 trgcgr.3 ⊢ φ → C - ˙ A = F - ˙ D
14 1 2 3 4 5 6 7 8 9 10 trgcgrg ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩ ↔ A - ˙ B = D - ˙ E ∧ B - ˙ C = E - ˙ F ∧ C - ˙ A = F - ˙ D
15 11 12 13 14 mpbir3and ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩