Metamath Proof Explorer


Theorem trisecnconstr

Description: Not all angles can be trisected. (Contributed by Thierry Arnoux, 15-Nov-2025)

Ref Expression
Assertion trisecnconstr ⊢ ¬ ∀ o ∈ Constr o 1 3 ∈ Constr

Proof

Step Hyp Ref Expression
1 eqid ⊢ e i ⁢ 2 ⁢ π 3 = e i ⁢ 2 ⁢ π 3
2 eqid ⊢ e i ⁢ 2 ⁢ π 3 1 3 = e i ⁢ 2 ⁢ π 3 1 3
3 1 2 cos9thpinconstr ⊢ e i ⁢ 2 ⁢ π 3 ∈ Constr ∧ e i ⁢ 2 ⁢ π 3 1 3 ∉ Constr
4 3 simpri ⊢ e i ⁢ 2 ⁢ π 3 1 3 ∉ Constr
5 4 neli ⊢ ¬ e i ⁢ 2 ⁢ π 3 1 3 ∈ Constr
6 3 simpli ⊢ e i ⁢ 2 ⁢ π 3 ∈ Constr
7 oveq1 ⊢ o = e i ⁢ 2 ⁢ π 3 → o 1 3 = e i ⁢ 2 ⁢ π 3 1 3
8 7 eleq1d ⊢ o = e i ⁢ 2 ⁢ π 3 → o 1 3 ∈ Constr ↔ e i ⁢ 2 ⁢ π 3 1 3 ∈ Constr
9 8 rspcv ⊢ e i ⁢ 2 ⁢ π 3 ∈ Constr → ∀ o ∈ Constr o 1 3 ∈ Constr → e i ⁢ 2 ⁢ π 3 1 3 ∈ Constr
10 6 9 ax-mp ⊢ ∀ o ∈ Constr o 1 3 ∈ Constr → e i ⁢ 2 ⁢ π 3 1 3 ∈ Constr
11 5 10 mto ⊢ ¬ ∀ o ∈ Constr o 1 3 ∈ Constr