Metamath Proof Explorer


Theorem triv1nsgd

Description: A trivial group has exactly one normal subgroup. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses triv1nsgd.1 ⊢ B = Base G
triv1nsgd.2 ⊢ 0 ˙ = 0 G
triv1nsgd.3 ⊢ φ → G ∈ Grp
triv1nsgd.4 ⊢ φ → B = 0 ˙
Assertion triv1nsgd ⊢ φ → NrmSGrp ⁡ G ≈ 1 𝑜

Proof

Step Hyp Ref Expression
1 triv1nsgd.1 ⊢ B = Base G
2 triv1nsgd.2 ⊢ 0 ˙ = 0 G
3 triv1nsgd.3 ⊢ φ → G ∈ Grp
4 triv1nsgd.4 ⊢ φ → B = 0 ˙
5 1 2 3 4 trivnsgd ⊢ φ → NrmSGrp ⁡ G = B
6 snex ⊢ 0 ˙ ∈ V
7 4 6 eqeltrdi ⊢ φ → B ∈ V
8 ensn1g ⊢ B ∈ V → B ≈ 1 𝑜
9 7 8 syl ⊢ φ → B ≈ 1 𝑜
10 5 9 eqbrtrd ⊢ φ → NrmSGrp ⁡ G ≈ 1 𝑜