Metamath Proof Explorer


Theorem trivnsgd

Description: The only normal subgroup of a trivial group is itself. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses trivnsgd.1 ⊢ B = Base G
trivnsgd.2 ⊢ 0 ˙ = 0 G
trivnsgd.3 ⊢ φ → G ∈ Grp
trivnsgd.4 ⊢ φ → B = 0 ˙
Assertion trivnsgd ⊢ φ → NrmSGrp ⁡ G = B

Proof

Step Hyp Ref Expression
1 trivnsgd.1 ⊢ B = Base G
2 trivnsgd.2 ⊢ 0 ˙ = 0 G
3 trivnsgd.3 ⊢ φ → G ∈ Grp
4 trivnsgd.4 ⊢ φ → B = 0 ˙
5 nsgsubg ⊢ x ∈ NrmSGrp ⁡ G → x ∈ SubGrp ⁡ G
6 5 a1i ⊢ φ → x ∈ NrmSGrp ⁡ G → x ∈ SubGrp ⁡ G
7 6 ssrdv ⊢ φ → NrmSGrp ⁡ G ⊆ SubGrp ⁡ G
8 1 2 3 4 trivsubgsnd ⊢ φ → SubGrp ⁡ G = B
9 7 8 sseqtrd ⊢ φ → NrmSGrp ⁡ G ⊆ B
10 1 nsgid ⊢ G ∈ Grp → B ∈ NrmSGrp ⁡ G
11 3 10 syl ⊢ φ → B ∈ NrmSGrp ⁡ G
12 11 snssd ⊢ φ → B ⊆ NrmSGrp ⁡ G
13 9 12 eqssd ⊢ φ → NrmSGrp ⁡ G = B