Metamath Proof Explorer


Theorem trivsubgd

Description: The only subgroup of a trivial group is itself. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses trivsubgd.1 ⊢ B = Base G
trivsubgd.2 ⊢ 0 ˙ = 0 G
trivsubgd.3 ⊢ φ → G ∈ Grp
trivsubgd.4 ⊢ φ → B = 0 ˙
trivsubgd.5 ⊢ φ → A ∈ SubGrp ⁡ G
Assertion trivsubgd ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 trivsubgd.1 ⊢ B = Base G
2 trivsubgd.2 ⊢ 0 ˙ = 0 G
3 trivsubgd.3 ⊢ φ → G ∈ Grp
4 trivsubgd.4 ⊢ φ → B = 0 ˙
5 trivsubgd.5 ⊢ φ → A ∈ SubGrp ⁡ G
6 1 subgss ⊢ A ∈ SubGrp ⁡ G → A ⊆ B
7 5 6 syl ⊢ φ → A ⊆ B
8 7 4 sseqtrd ⊢ φ → A ⊆ 0 ˙
9 2 subg0cl ⊢ A ∈ SubGrp ⁡ G → 0 ˙ ∈ A
10 5 9 syl ⊢ φ → 0 ˙ ∈ A
11 10 snssd ⊢ φ → 0 ˙ ⊆ A
12 8 11 eqssd ⊢ φ → A = 0 ˙
13 12 4 eqtr4d ⊢ φ → A = B