Metamath Proof Explorer


Theorem trljco2

Description: Trace joined with trace of composition. (Contributed by NM, 16-Jun-2013)

Ref Expression
Hypotheses trljco.j ⊢ ∨ ˙ = join ⁡ K
trljco.h ⊢ H = LHyp ⁡ K
trljco.t ⊢ T = LTrn ⁡ K ⁡ W
trljco.r ⊢ R = trL ⁡ K ⁡ W
Assertion trljco2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∨ ˙ R ⁡ F ∘ G = R ⁡ G ∨ ˙ R ⁡ F ∘ G

Proof

Step Hyp Ref Expression
1 trljco.j ⊢ ∨ ˙ = join ⁡ K
2 trljco.h ⊢ H = LHyp ⁡ K
3 trljco.t ⊢ T = LTrn ⁡ K ⁡ W
4 trljco.r ⊢ R = trL ⁡ K ⁡ W
5 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → K ∈ HL
6 5 hllatd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → K ∈ Lat
7 eqid ⊢ Base K = Base K
8 7 2 3 4 trlcl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → R ⁡ F ∈ Base K
9 8 3adant3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∈ Base K
10 7 2 3 4 trlcl ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T → R ⁡ G ∈ Base K
11 10 3adant2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ G ∈ Base K
12 7 1 latjcom ⊢ K ∈ Lat ∧ R ⁡ F ∈ Base K ∧ R ⁡ G ∈ Base K → R ⁡ F ∨ ˙ R ⁡ G = R ⁡ G ∨ ˙ R ⁡ F
13 6 9 11 12 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∨ ˙ R ⁡ G = R ⁡ G ∨ ˙ R ⁡ F
14 1 2 3 4 trljco ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T ∧ F ∈ T → R ⁡ G ∨ ˙ R ⁡ G ∘ F = R ⁡ G ∨ ˙ R ⁡ F
15 14 3com23 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ G ∨ ˙ R ⁡ G ∘ F = R ⁡ G ∨ ˙ R ⁡ F
16 13 15 eqtr4d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∨ ˙ R ⁡ G = R ⁡ G ∨ ˙ R ⁡ G ∘ F
17 1 2 3 4 trljco ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∨ ˙ R ⁡ F ∘ G = R ⁡ F ∨ ˙ R ⁡ G
18 2 3 ltrncom ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → F ∘ G = G ∘ F
19 18 fveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∘ G = R ⁡ G ∘ F
20 19 oveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ G ∨ ˙ R ⁡ F ∘ G = R ⁡ G ∨ ˙ R ⁡ G ∘ F
21 16 17 20 3eqtr4d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → R ⁡ F ∨ ˙ R ⁡ F ∘ G = R ⁡ G ∨ ˙ R ⁡ F ∘ G