Metamath Proof Explorer


Theorem undi

Description: Distributive law for union over intersection. Exercise 11 of TakeutiZaring p. 17. (Contributed by NM, 30-Sep-2002) (Proof shortened by Andrew Salmon, 26-Jun-2011)

Ref Expression
Assertion undi ⊢ A ∪ B ∩ C = A ∪ B ∩ A ∪ C

Proof

Step Hyp Ref Expression
1 elin ⊢ x ∈ B ∩ C ↔ x ∈ B ∧ x ∈ C
2 1 orbi2i ⊢ x ∈ A ∨ x ∈ B ∩ C ↔ x ∈ A ∨ x ∈ B ∧ x ∈ C
3 ordi ⊢ x ∈ A ∨ x ∈ B ∧ x ∈ C ↔ x ∈ A ∨ x ∈ B ∧ x ∈ A ∨ x ∈ C
4 elin ⊢ x ∈ A ∪ B ∩ A ∪ C ↔ x ∈ A ∪ B ∧ x ∈ A ∪ C
5 elun ⊢ x ∈ A ∪ B ↔ x ∈ A ∨ x ∈ B
6 elun ⊢ x ∈ A ∪ C ↔ x ∈ A ∨ x ∈ C
7 5 6 anbi12i ⊢ x ∈ A ∪ B ∧ x ∈ A ∪ C ↔ x ∈ A ∨ x ∈ B ∧ x ∈ A ∨ x ∈ C
8 4 7 bitr2i ⊢ x ∈ A ∨ x ∈ B ∧ x ∈ A ∨ x ∈ C ↔ x ∈ A ∪ B ∩ A ∪ C
9 2 3 8 3bitri ⊢ x ∈ A ∨ x ∈ B ∩ C ↔ x ∈ A ∪ B ∩ A ∪ C
10 9 uneqri ⊢ A ∪ B ∩ C = A ∪ B ∩ A ∪ C