Metamath Proof Explorer


Theorem unissd

Description: Subclass relationship for subclass union. Deduction form of uniss . (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypothesis unissd.1 φ A B
Assertion unissd φ A B

Proof

Step Hyp Ref Expression
1 unissd.1 φ A B
2 uniss A B A B
3 1 2 syl φ A B