Metamath Proof Explorer
Description: Subclass relationship for subclass union. Deduction form of uniss .
(Contributed by David Moews, 1-May-2017)
|
|
Ref |
Expression |
|
Hypothesis |
unissd.1 |
|
|
Assertion |
unissd |
|
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
unissd.1 |
|
2 |
|
uniss |
|
3 |
1 2
|
syl |
|