Metamath Proof Explorer


Theorem unitnz

Description: In a nonzero ring, a unit cannot be zero. (Contributed by Thierry Arnoux, 25-Apr-2025)

Ref Expression
Hypotheses unitnz.1 ⊢ U = Unit ⁡ R
unitnz.2 ⊢ 0 ˙ = 0 R
unitnz.3 ⊢ φ → R ∈ NzRing
unitnz.4 ⊢ φ → X ∈ U
Assertion unitnz ⊢ φ → X ≠ 0 ˙

Proof

Step Hyp Ref Expression
1 unitnz.1 ⊢ U = Unit ⁡ R
2 unitnz.2 ⊢ 0 ˙ = 0 R
3 unitnz.3 ⊢ φ → R ∈ NzRing
4 unitnz.4 ⊢ φ → X ∈ U
5 nzrring ⊢ R ∈ NzRing → R ∈ Ring
6 3 5 syl ⊢ φ → R ∈ Ring
7 eqid ⊢ 1 R = 1 R
8 7 2 nzrnz ⊢ R ∈ NzRing → 1 R ≠ 0 ˙
9 3 8 syl ⊢ φ → 1 R ≠ 0 ˙
10 1 2 7 0unit ⊢ R ∈ Ring → 0 ˙ ∈ U ↔ 1 R = 0 ˙
11 10 necon3bbid ⊢ R ∈ Ring → ¬ 0 ˙ ∈ U ↔ 1 R ≠ 0 ˙
12 11 biimpar ⊢ R ∈ Ring ∧ 1 R ≠ 0 ˙ → ¬ 0 ˙ ∈ U
13 6 9 12 syl2anc ⊢ φ → ¬ 0 ˙ ∈ U
14 nelne2 ⊢ X ∈ U ∧ ¬ 0 ˙ ∈ U → X ≠ 0 ˙
15 4 13 14 syl2anc ⊢ φ → X ≠ 0 ˙