Metamath Proof Explorer


Theorem uniwf

Description: A union is well-founded iff the base set is. (Contributed by Mario Carneiro, 8-Jun-2013) (Revised by Mario Carneiro, 17-Nov-2014)

Ref Expression
Assertion uniwf ⊢ A ∈ ⋃ R1 On ↔ ⋃ A ∈ ⋃ R1 On

Proof

Step Hyp Ref Expression
1 r1tr ⊢ Tr ⁡ R1 ⁡ suc ⁡ rank ⁡ A
2 rankidb ⊢ A ∈ ⋃ R1 On → A ∈ R1 ⁡ suc ⁡ rank ⁡ A
3 trss ⊢ Tr ⁡ R1 ⁡ suc ⁡ rank ⁡ A → A ∈ R1 ⁡ suc ⁡ rank ⁡ A → A ⊆ R1 ⁡ suc ⁡ rank ⁡ A
4 1 2 3 mpsyl ⊢ A ∈ ⋃ R1 On → A ⊆ R1 ⁡ suc ⁡ rank ⁡ A
5 rankdmr1 ⊢ rank ⁡ A ∈ dom ⁡ R1
6 r1sucg ⊢ rank ⁡ A ∈ dom ⁡ R1 → R1 ⁡ suc ⁡ rank ⁡ A = 𝒫 R1 ⁡ rank ⁡ A
7 5 6 ax-mp ⊢ R1 ⁡ suc ⁡ rank ⁡ A = 𝒫 R1 ⁡ rank ⁡ A
8 4 7 sseqtrdi ⊢ A ∈ ⋃ R1 On → A ⊆ 𝒫 R1 ⁡ rank ⁡ A
9 sspwuni ⊢ A ⊆ 𝒫 R1 ⁡ rank ⁡ A ↔ ⋃ A ⊆ R1 ⁡ rank ⁡ A
10 8 9 sylib ⊢ A ∈ ⋃ R1 On → ⋃ A ⊆ R1 ⁡ rank ⁡ A
11 fvex ⊢ R1 ⁡ rank ⁡ A ∈ V
12 11 elpw2 ⊢ ⋃ A ∈ 𝒫 R1 ⁡ rank ⁡ A ↔ ⋃ A ⊆ R1 ⁡ rank ⁡ A
13 10 12 sylibr ⊢ A ∈ ⋃ R1 On → ⋃ A ∈ 𝒫 R1 ⁡ rank ⁡ A
14 13 7 eleqtrrdi ⊢ A ∈ ⋃ R1 On → ⋃ A ∈ R1 ⁡ suc ⁡ rank ⁡ A
15 r1elwf ⊢ ⋃ A ∈ R1 ⁡ suc ⁡ rank ⁡ A → ⋃ A ∈ ⋃ R1 On
16 14 15 syl ⊢ A ∈ ⋃ R1 On → ⋃ A ∈ ⋃ R1 On
17 pwwf ⊢ ⋃ A ∈ ⋃ R1 On ↔ 𝒫 ⋃ A ∈ ⋃ R1 On
18 pwuni ⊢ A ⊆ 𝒫 ⋃ A
19 sswf ⊢ 𝒫 ⋃ A ∈ ⋃ R1 On ∧ A ⊆ 𝒫 ⋃ A → A ∈ ⋃ R1 On
20 18 19 mpan2 ⊢ 𝒫 ⋃ A ∈ ⋃ R1 On → A ∈ ⋃ R1 On
21 17 20 sylbi ⊢ ⋃ A ∈ ⋃ R1 On → A ∈ ⋃ R1 On
22 16 21 impbii ⊢ A ∈ ⋃ R1 On ↔ ⋃ A ∈ ⋃ R1 On