Metamath Proof Explorer


Theorem usgreqdrusgr

Description: If all vertices in a simple graph have the same degree, the graph is k-regular. (Contributed by AV, 26-Dec-2020)

Ref Expression
Hypotheses isrusgr0.v ⊢ V = Vtx ⁡ G
isrusgr0.d ⊢ D = VtxDeg ⁡ G
Assertion usgreqdrusgr ⊢ G ∈ USGraph ∧ K ∈ ℕ 0 * ∧ ∀ v ∈ V D ⁡ v = K → G RegUSGraph K

Proof

Step Hyp Ref Expression
1 isrusgr0.v ⊢ V = Vtx ⁡ G
2 isrusgr0.d ⊢ D = VtxDeg ⁡ G
3 1 2 isrusgr0 ⊢ G ∈ USGraph ∧ K ∈ ℕ 0 * → G RegUSGraph K ↔ G ∈ USGraph ∧ K ∈ ℕ 0 * ∧ ∀ v ∈ V D ⁡ v = K
4 3 3adant3 ⊢ G ∈ USGraph ∧ K ∈ ℕ 0 * ∧ ∀ v ∈ V D ⁡ v = K → G RegUSGraph K ↔ G ∈ USGraph ∧ K ∈ ℕ 0 * ∧ ∀ v ∈ V D ⁡ v = K
5 4 ibir ⊢ G ∈ USGraph ∧ K ∈ ℕ 0 * ∧ ∀ v ∈ V D ⁡ v = K → G RegUSGraph K