Metamath Proof Explorer


Theorem usgrvd00

Description: If every vertex in a simple graph has degree 0, there is no edge in the graph. (Contributed by Alexander van der Vekens, 12-Jul-2018) (Revised by AV, 17-Dec-2020) (Proof shortened by AV, 23-Dec-2020)

Ref Expression
Hypotheses vtxdusgradjvtx.v ⊢ V = Vtx ⁡ G
vtxdusgradjvtx.e ⊢ E = Edg ⁡ G
Assertion usgrvd00 ⊢ G ∈ USGraph → ∀ v ∈ V VtxDeg ⁡ G ⁡ v = 0 → E = ∅

Proof

Step Hyp Ref Expression
1 vtxdusgradjvtx.v ⊢ V = Vtx ⁡ G
2 vtxdusgradjvtx.e ⊢ E = Edg ⁡ G
3 usgruhgr ⊢ G ∈ USGraph → G ∈ UHGraph
4 1 2 uhgrvd00 ⊢ G ∈ UHGraph → ∀ v ∈ V VtxDeg ⁡ G ⁡ v = 0 → E = ∅
5 3 4 syl ⊢ G ∈ USGraph → ∀ v ∈ V VtxDeg ⁡ G ⁡ v = 0 → E = ∅