Metamath Proof Explorer


Theorem wlkp1lem1

Description: Lemma for wlkp1 . (Contributed by AV, 6-Mar-2021)

Ref Expression
Hypotheses wlkp1.v ⊢ V = Vtx ⁡ G
wlkp1.i ⊢ I = iEdg ⁡ G
wlkp1.f ⊢ φ → Fun ⁡ I
wlkp1.a ⊢ φ → I ∈ Fin
wlkp1.b ⊢ φ → B ∈ W
wlkp1.c ⊢ φ → C ∈ V
wlkp1.d ⊢ φ → ¬ B ∈ dom ⁡ I
wlkp1.w ⊢ φ → F Walks ⁡ G P
wlkp1.n ⊢ N = F
Assertion wlkp1lem1 ⊢ φ → ¬ N + 1 ∈ dom ⁡ P

Proof

Step Hyp Ref Expression
1 wlkp1.v ⊢ V = Vtx ⁡ G
2 wlkp1.i ⊢ I = iEdg ⁡ G
3 wlkp1.f ⊢ φ → Fun ⁡ I
4 wlkp1.a ⊢ φ → I ∈ Fin
5 wlkp1.b ⊢ φ → B ∈ W
6 wlkp1.c ⊢ φ → C ∈ V
7 wlkp1.d ⊢ φ → ¬ B ∈ dom ⁡ I
8 wlkp1.w ⊢ φ → F Walks ⁡ G P
9 wlkp1.n ⊢ N = F
10 wlkcl ⊢ F Walks ⁡ G P → F ∈ ℕ 0
11 1 wlkp ⊢ F Walks ⁡ G P → P : 0 … F ⟶ V
12 10 11 jca ⊢ F Walks ⁡ G P → F ∈ ℕ 0 ∧ P : 0 … F ⟶ V
13 fzp1nel ⊢ ¬ F + 1 ∈ 0 … F
14 13 a1i ⊢ F ∈ ℕ 0 → ¬ F + 1 ∈ 0 … F
15 9 oveq1i ⊢ N + 1 = F + 1
16 15 eleq1i ⊢ N + 1 ∈ 0 … F ↔ F + 1 ∈ 0 … F
17 14 16 sylnibr ⊢ F ∈ ℕ 0 → ¬ N + 1 ∈ 0 … F
18 eleq2 ⊢ dom ⁡ P = 0 … F → N + 1 ∈ dom ⁡ P ↔ N + 1 ∈ 0 … F
19 18 notbid ⊢ dom ⁡ P = 0 … F → ¬ N + 1 ∈ dom ⁡ P ↔ ¬ N + 1 ∈ 0 … F
20 17 19 syl5ibrcom ⊢ F ∈ ℕ 0 → dom ⁡ P = 0 … F → ¬ N + 1 ∈ dom ⁡ P
21 fdm ⊢ P : 0 … F ⟶ V → dom ⁡ P = 0 … F
22 20 21 impel ⊢ F ∈ ℕ 0 ∧ P : 0 … F ⟶ V → ¬ N + 1 ∈ dom ⁡ P
23 8 12 22 3syl ⊢ φ → ¬ N + 1 ∈ dom ⁡ P