Metamath Proof Explorer


Theorem wrdlen2i

Description: Implications of a word of length two. (Contributed by AV, 27-Jul-2018) (Proof shortened by AV, 14-Oct-2018)

Ref Expression
Assertion wrdlen2i ⊢ S ∈ V ∧ T ∈ V → W = 0 S 1 T → W ∈ Word V ∧ W = 2 ∧ W ⁡ 0 = S ∧ W ⁡ 1 = T

Proof

Step Hyp Ref Expression
1 c0ex ⊢ 0 ∈ V
2 1ex ⊢ 1 ∈ V
3 1 2 pm3.2i ⊢ 0 ∈ V ∧ 1 ∈ V
4 simpl ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → S ∈ V ∧ T ∈ V
5 0ne1 ⊢ 0 ≠ 1
6 5 a1i ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → 0 ≠ 1
7 fprg ⊢ 0 ∈ V ∧ 1 ∈ V ∧ S ∈ V ∧ T ∈ V ∧ 0 ≠ 1 → 0 S 1 T : 0 1 ⟶ S T
8 3 4 6 7 mp3an2i ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → 0 S 1 T : 0 1 ⟶ S T
9 fzo0to2pr ⊢ 0 ..^ 2 = 0 1
10 9 eqcomi ⊢ 0 1 = 0 ..^ 2
11 10 a1i ⊢ S ∈ V ∧ T ∈ V → 0 1 = 0 ..^ 2
12 11 feq2d ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T : 0 1 ⟶ S T ↔ 0 S 1 T : 0 ..^ 2 ⟶ S T
13 12 biimpa ⊢ S ∈ V ∧ T ∈ V ∧ 0 S 1 T : 0 1 ⟶ S T → 0 S 1 T : 0 ..^ 2 ⟶ S T
14 prssi ⊢ S ∈ V ∧ T ∈ V → S T ⊆ V
15 14 adantr ⊢ S ∈ V ∧ T ∈ V ∧ 0 S 1 T : 0 1 ⟶ S T → S T ⊆ V
16 13 15 fssd ⊢ S ∈ V ∧ T ∈ V ∧ 0 S 1 T : 0 1 ⟶ S T → 0 S 1 T : 0 ..^ 2 ⟶ V
17 16 ex ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T : 0 1 ⟶ S T → 0 S 1 T : 0 ..^ 2 ⟶ V
18 17 adantr ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → 0 S 1 T : 0 1 ⟶ S T → 0 S 1 T : 0 ..^ 2 ⟶ V
19 18 impcom ⊢ 0 S 1 T : 0 1 ⟶ S T ∧ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → 0 S 1 T : 0 ..^ 2 ⟶ V
20 feq1 ⊢ W = 0 S 1 T → W : 0 ..^ 2 ⟶ V ↔ 0 S 1 T : 0 ..^ 2 ⟶ V
21 20 adantl ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W : 0 ..^ 2 ⟶ V ↔ 0 S 1 T : 0 ..^ 2 ⟶ V
22 21 adantl ⊢ 0 S 1 T : 0 1 ⟶ S T ∧ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W : 0 ..^ 2 ⟶ V ↔ 0 S 1 T : 0 ..^ 2 ⟶ V
23 19 22 mpbird ⊢ 0 S 1 T : 0 1 ⟶ S T ∧ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W : 0 ..^ 2 ⟶ V
24 8 23 mpancom ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W : 0 ..^ 2 ⟶ V
25 iswrdi ⊢ W : 0 ..^ 2 ⟶ V → W ∈ Word V
26 24 25 syl ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W ∈ Word V
27 fveq2 ⊢ W = 0 S 1 T → W = 0 S 1 T
28 5 neii ⊢ ¬ 0 = 1
29 simpl ⊢ S ∈ V ∧ T ∈ V → S ∈ V
30 opth1g ⊢ 0 ∈ V ∧ S ∈ V → 0 S = 1 T → 0 = 1
31 1 29 30 sylancr ⊢ S ∈ V ∧ T ∈ V → 0 S = 1 T → 0 = 1
32 28 31 mtoi ⊢ S ∈ V ∧ T ∈ V → ¬ 0 S = 1 T
33 32 neqned ⊢ S ∈ V ∧ T ∈ V → 0 S ≠ 1 T
34 opex ⊢ 0 S ∈ V
35 opex ⊢ 1 T ∈ V
36 34 35 pm3.2i ⊢ 0 S ∈ V ∧ 1 T ∈ V
37 hashprg ⊢ 0 S ∈ V ∧ 1 T ∈ V → 0 S ≠ 1 T ↔ 0 S 1 T = 2
38 36 37 mp1i ⊢ S ∈ V ∧ T ∈ V → 0 S ≠ 1 T ↔ 0 S 1 T = 2
39 33 38 mpbid ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T = 2
40 27 39 sylan9eqr ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W = 2
41 5 a1i ⊢ S ∈ V ∧ T ∈ V → 0 ≠ 1
42 fvpr1g ⊢ 0 ∈ V ∧ S ∈ V ∧ 0 ≠ 1 → 0 S 1 T ⁡ 0 = S
43 1 29 41 42 mp3an2i ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T ⁡ 0 = S
44 simpr ⊢ S ∈ V ∧ T ∈ V → T ∈ V
45 fvpr2g ⊢ 1 ∈ V ∧ T ∈ V ∧ 0 ≠ 1 → 0 S 1 T ⁡ 1 = T
46 2 44 41 45 mp3an2i ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T ⁡ 1 = T
47 43 46 jca ⊢ S ∈ V ∧ T ∈ V → 0 S 1 T ⁡ 0 = S ∧ 0 S 1 T ⁡ 1 = T
48 47 adantr ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → 0 S 1 T ⁡ 0 = S ∧ 0 S 1 T ⁡ 1 = T
49 fveq1 ⊢ W = 0 S 1 T → W ⁡ 0 = 0 S 1 T ⁡ 0
50 49 eqeq1d ⊢ W = 0 S 1 T → W ⁡ 0 = S ↔ 0 S 1 T ⁡ 0 = S
51 fveq1 ⊢ W = 0 S 1 T → W ⁡ 1 = 0 S 1 T ⁡ 1
52 51 eqeq1d ⊢ W = 0 S 1 T → W ⁡ 1 = T ↔ 0 S 1 T ⁡ 1 = T
53 50 52 anbi12d ⊢ W = 0 S 1 T → W ⁡ 0 = S ∧ W ⁡ 1 = T ↔ 0 S 1 T ⁡ 0 = S ∧ 0 S 1 T ⁡ 1 = T
54 53 adantl ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W ⁡ 0 = S ∧ W ⁡ 1 = T ↔ 0 S 1 T ⁡ 0 = S ∧ 0 S 1 T ⁡ 1 = T
55 48 54 mpbird ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W ⁡ 0 = S ∧ W ⁡ 1 = T
56 26 40 55 jca31 ⊢ S ∈ V ∧ T ∈ V ∧ W = 0 S 1 T → W ∈ Word V ∧ W = 2 ∧ W ⁡ 0 = S ∧ W ⁡ 1 = T
57 56 ex ⊢ S ∈ V ∧ T ∈ V → W = 0 S 1 T → W ∈ Word V ∧ W = 2 ∧ W ⁡ 0 = S ∧ W ⁡ 1 = T