Metamath Proof Explorer


Theorem xdivval

Description: Value of division: the (unique) element x such that ( B x. x ) = A . This is meaningful only when B is nonzero. (Contributed by Thierry Arnoux, 17-Dec-2016)

Ref Expression
Assertion xdivval ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A

Proof

Step Hyp Ref Expression
1 eldifsn ⊢ B ∈ ℝ ∖ 0 ↔ B ∈ ℝ ∧ B ≠ 0
2 simpl ⊢ y = A ∧ x ∈ ℝ * → y = A
3 2 eqeq2d ⊢ y = A ∧ x ∈ ℝ * → z ⋅ 𝑒 x = y ↔ z ⋅ 𝑒 x = A
4 3 riotabidva ⊢ y = A → ι x ∈ ℝ * | z ⋅ 𝑒 x = y = ι x ∈ ℝ * | z ⋅ 𝑒 x = A
5 simpl ⊢ z = B ∧ x ∈ ℝ * → z = B
6 5 oveq1d ⊢ z = B ∧ x ∈ ℝ * → z ⋅ 𝑒 x = B ⋅ 𝑒 x
7 6 eqeq1d ⊢ z = B ∧ x ∈ ℝ * → z ⋅ 𝑒 x = A ↔ B ⋅ 𝑒 x = A
8 7 riotabidva ⊢ z = B → ι x ∈ ℝ * | z ⋅ 𝑒 x = A = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
9 df-xdiv ⊢ ÷ 𝑒 = y ∈ ℝ * , z ∈ ℝ ∖ 0 ⟼ ι x ∈ ℝ * | z ⋅ 𝑒 x = y
10 riotaex ⊢ ι x ∈ ℝ * | B ⋅ 𝑒 x = A ∈ V
11 4 8 9 10 ovmpo ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∖ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
12 1 11 sylan2br ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
13 12 3impb ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A