Metamath Proof Explorer


Theorem xmulasslem

Description: Lemma for xmulass . (Contributed by Mario Carneiro, 20-Aug-2015)

Ref Expression
Hypotheses xmulasslem.1 ⊢ x = D → ψ ↔ X = Y
xmulasslem.2 ⊢ x = − D → ψ ↔ E = F
xmulasslem.x ⊢ φ → X ∈ ℝ *
xmulasslem.y ⊢ φ → Y ∈ ℝ *
xmulasslem.d ⊢ φ → D ∈ ℝ *
xmulasslem.ps ⊢ φ ∧ x ∈ ℝ * ∧ 0 < x → ψ
xmulasslem.0 ⊢ φ → x = 0 → ψ
xmulasslem.e ⊢ φ → E = − X
xmulasslem.f ⊢ φ → F = − Y
Assertion xmulasslem ⊢ φ → X = Y

Proof

Step Hyp Ref Expression
1 xmulasslem.1 ⊢ x = D → ψ ↔ X = Y
2 xmulasslem.2 ⊢ x = − D → ψ ↔ E = F
3 xmulasslem.x ⊢ φ → X ∈ ℝ *
4 xmulasslem.y ⊢ φ → Y ∈ ℝ *
5 xmulasslem.d ⊢ φ → D ∈ ℝ *
6 xmulasslem.ps ⊢ φ ∧ x ∈ ℝ * ∧ 0 < x → ψ
7 xmulasslem.0 ⊢ φ → x = 0 → ψ
8 xmulasslem.e ⊢ φ → E = − X
9 xmulasslem.f ⊢ φ → F = − Y
10 0xr ⊢ 0 ∈ ℝ *
11 xrltso ⊢ < Or ℝ *
12 solin ⊢ < Or ℝ * ∧ D ∈ ℝ * ∧ 0 ∈ ℝ * → D < 0 ∨ D = 0 ∨ 0 < D
13 11 12 mpan ⊢ D ∈ ℝ * ∧ 0 ∈ ℝ * → D < 0 ∨ D = 0 ∨ 0 < D
14 5 10 13 sylancl ⊢ φ → D < 0 ∨ D = 0 ∨ 0 < D
15 xlt0neg1 ⊢ D ∈ ℝ * → D < 0 ↔ 0 < − D
16 5 15 syl ⊢ φ → D < 0 ↔ 0 < − D
17 xnegcl ⊢ D ∈ ℝ * → − D ∈ ℝ *
18 5 17 syl ⊢ φ → − D ∈ ℝ *
19 breq2 ⊢ x = − D → 0 < x ↔ 0 < − D
20 19 2 imbi12d ⊢ x = − D → 0 < x → ψ ↔ 0 < − D → E = F
21 20 imbi2d ⊢ x = − D → φ → 0 < x → ψ ↔ φ → 0 < − D → E = F
22 6 exp32 ⊢ φ → x ∈ ℝ * → 0 < x → ψ
23 22 com12 ⊢ x ∈ ℝ * → φ → 0 < x → ψ
24 21 23 vtoclga ⊢ − D ∈ ℝ * → φ → 0 < − D → E = F
25 18 24 mpcom ⊢ φ → 0 < − D → E = F
26 16 25 sylbid ⊢ φ → D < 0 → E = F
27 8 9 eqeq12d ⊢ φ → E = F ↔ − X = − Y
28 xneg11 ⊢ X ∈ ℝ * ∧ Y ∈ ℝ * → − X = − Y ↔ X = Y
29 3 4 28 syl2anc ⊢ φ → − X = − Y ↔ X = Y
30 27 29 bitrd ⊢ φ → E = F ↔ X = Y
31 26 30 sylibd ⊢ φ → D < 0 → X = Y
32 eqeq1 ⊢ x = D → x = 0 ↔ D = 0
33 32 1 imbi12d ⊢ x = D → x = 0 → ψ ↔ D = 0 → X = Y
34 33 imbi2d ⊢ x = D → φ → x = 0 → ψ ↔ φ → D = 0 → X = Y
35 34 7 vtoclg ⊢ D ∈ ℝ * → φ → D = 0 → X = Y
36 5 35 mpcom ⊢ φ → D = 0 → X = Y
37 breq2 ⊢ x = D → 0 < x ↔ 0 < D
38 37 1 imbi12d ⊢ x = D → 0 < x → ψ ↔ 0 < D → X = Y
39 38 imbi2d ⊢ x = D → φ → 0 < x → ψ ↔ φ → 0 < D → X = Y
40 39 23 vtoclga ⊢ D ∈ ℝ * → φ → 0 < D → X = Y
41 5 40 mpcom ⊢ φ → 0 < D → X = Y
42 31 36 41 3jaod ⊢ φ → D < 0 ∨ D = 0 ∨ 0 < D → X = Y
43 14 42 mpd ⊢ φ → X = Y