Metamath Proof Explorer


Theorem xpcco2nd

Description: Value of composition in the binary product of categories. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses xpcco1st.t ⊢ T = C × c D
xpcco1st.b ⊢ B = Base T
xpcco1st.k ⊢ K = Hom ⁡ T
xpcco1st.o ⊢ O = comp ⁡ T
xpcco1st.x ⊢ φ → X ∈ B
xpcco1st.y ⊢ φ → Y ∈ B
xpcco1st.z ⊢ φ → Z ∈ B
xpcco1st.f ⊢ φ → F ∈ X K Y
xpcco1st.g ⊢ φ → G ∈ Y K Z
xpcco2nd.1 ⊢ · ˙ = comp ⁡ D
Assertion xpcco2nd ⊢ φ → 2 nd ⁡ G X Y O Z F = 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F

Proof

Step Hyp Ref Expression
1 xpcco1st.t ⊢ T = C × c D
2 xpcco1st.b ⊢ B = Base T
3 xpcco1st.k ⊢ K = Hom ⁡ T
4 xpcco1st.o ⊢ O = comp ⁡ T
5 xpcco1st.x ⊢ φ → X ∈ B
6 xpcco1st.y ⊢ φ → Y ∈ B
7 xpcco1st.z ⊢ φ → Z ∈ B
8 xpcco1st.f ⊢ φ → F ∈ X K Y
9 xpcco1st.g ⊢ φ → G ∈ Y K Z
10 xpcco2nd.1 ⊢ · ˙ = comp ⁡ D
11 eqid ⊢ comp ⁡ C = comp ⁡ C
12 1 2 3 11 10 4 5 6 7 8 9 xpcco ⊢ φ → G X Y O Z F = 1 st ⁡ G 1 st ⁡ X 1 st ⁡ Y comp ⁡ C 1 st ⁡ Z 1 st ⁡ F 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F
13 ovex ⊢ 1 st ⁡ G 1 st ⁡ X 1 st ⁡ Y comp ⁡ C 1 st ⁡ Z 1 st ⁡ F ∈ V
14 ovex ⊢ 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F ∈ V
15 13 14 op2ndd ⊢ G X Y O Z F = 1 st ⁡ G 1 st ⁡ X 1 st ⁡ Y comp ⁡ C 1 st ⁡ Z 1 st ⁡ F 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F → 2 nd ⁡ G X Y O Z F = 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F
16 12 15 syl ⊢ φ → 2 nd ⁡ G X Y O Z F = 2 nd ⁡ G 2 nd ⁡ X 2 nd ⁡ Y · ˙ 2 nd ⁡ Z 2 nd ⁡ F