Metamath Proof Explorer


Theorem xpchom

Description: Set of morphisms of the binary product of categories. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses xpchomfval.t ⊢ T = C × c D
xpchomfval.y ⊢ B = Base T
xpchomfval.h ⊢ H = Hom ⁡ C
xpchomfval.j ⊢ J = Hom ⁡ D
xpchomfval.k ⊢ K = Hom ⁡ T
xpchom.x ⊢ φ → X ∈ B
xpchom.y ⊢ φ → Y ∈ B
Assertion xpchom ⊢ φ → X K Y = 1 st ⁡ X H 1 st ⁡ Y × 2 nd ⁡ X J 2 nd ⁡ Y

Proof

Step Hyp Ref Expression
1 xpchomfval.t ⊢ T = C × c D
2 xpchomfval.y ⊢ B = Base T
3 xpchomfval.h ⊢ H = Hom ⁡ C
4 xpchomfval.j ⊢ J = Hom ⁡ D
5 xpchomfval.k ⊢ K = Hom ⁡ T
6 xpchom.x ⊢ φ → X ∈ B
7 xpchom.y ⊢ φ → Y ∈ B
8 simpl ⊢ u = X ∧ v = Y → u = X
9 8 fveq2d ⊢ u = X ∧ v = Y → 1 st ⁡ u = 1 st ⁡ X
10 simpr ⊢ u = X ∧ v = Y → v = Y
11 10 fveq2d ⊢ u = X ∧ v = Y → 1 st ⁡ v = 1 st ⁡ Y
12 9 11 oveq12d ⊢ u = X ∧ v = Y → 1 st ⁡ u H 1 st ⁡ v = 1 st ⁡ X H 1 st ⁡ Y
13 8 fveq2d ⊢ u = X ∧ v = Y → 2 nd ⁡ u = 2 nd ⁡ X
14 10 fveq2d ⊢ u = X ∧ v = Y → 2 nd ⁡ v = 2 nd ⁡ Y
15 13 14 oveq12d ⊢ u = X ∧ v = Y → 2 nd ⁡ u J 2 nd ⁡ v = 2 nd ⁡ X J 2 nd ⁡ Y
16 12 15 xpeq12d ⊢ u = X ∧ v = Y → 1 st ⁡ u H 1 st ⁡ v × 2 nd ⁡ u J 2 nd ⁡ v = 1 st ⁡ X H 1 st ⁡ Y × 2 nd ⁡ X J 2 nd ⁡ Y
17 1 2 3 4 5 xpchomfval ⊢ K = u ∈ B , v ∈ B ⟼ 1 st ⁡ u H 1 st ⁡ v × 2 nd ⁡ u J 2 nd ⁡ v
18 ovex ⊢ 1 st ⁡ X H 1 st ⁡ Y ∈ V
19 ovex ⊢ 2 nd ⁡ X J 2 nd ⁡ Y ∈ V
20 18 19 xpex ⊢ 1 st ⁡ X H 1 st ⁡ Y × 2 nd ⁡ X J 2 nd ⁡ Y ∈ V
21 16 17 20 ovmpoa ⊢ X ∈ B ∧ Y ∈ B → X K Y = 1 st ⁡ X H 1 st ⁡ Y × 2 nd ⁡ X J 2 nd ⁡ Y
22 6 7 21 syl2anc ⊢ φ → X K Y = 1 st ⁡ X H 1 st ⁡ Y × 2 nd ⁡ X J 2 nd ⁡ Y