Metamath Proof Explorer


Theorem xpen

Description: Equinumerosity law for Cartesian product. Proposition 4.22(b) of Mendelson p. 254. (Contributed by NM, 24-Jul-2004) (Proof shortened by Mario Carneiro, 26-Apr-2015)

Ref Expression
Assertion xpen ⊢ A ≈ B ∧ C ≈ D → A × C ≈ B × D

Proof

Step Hyp Ref Expression
1 relen ⊢ Rel ⁡ ≈
2 1 brrelex1i ⊢ C ≈ D → C ∈ V
3 endom ⊢ A ≈ B → A ≼ B
4 xpdom1g ⊢ C ∈ V ∧ A ≼ B → A × C ≼ B × C
5 2 3 4 syl2anr ⊢ A ≈ B ∧ C ≈ D → A × C ≼ B × C
6 1 brrelex2i ⊢ A ≈ B → B ∈ V
7 endom ⊢ C ≈ D → C ≼ D
8 xpdom2g ⊢ B ∈ V ∧ C ≼ D → B × C ≼ B × D
9 6 7 8 syl2an ⊢ A ≈ B ∧ C ≈ D → B × C ≼ B × D
10 domtr ⊢ A × C ≼ B × C ∧ B × C ≼ B × D → A × C ≼ B × D
11 5 9 10 syl2anc ⊢ A ≈ B ∧ C ≈ D → A × C ≼ B × D
12 1 brrelex2i ⊢ C ≈ D → D ∈ V
13 ensym ⊢ A ≈ B → B ≈ A
14 endom ⊢ B ≈ A → B ≼ A
15 13 14 syl ⊢ A ≈ B → B ≼ A
16 xpdom1g ⊢ D ∈ V ∧ B ≼ A → B × D ≼ A × D
17 12 15 16 syl2anr ⊢ A ≈ B ∧ C ≈ D → B × D ≼ A × D
18 1 brrelex1i ⊢ A ≈ B → A ∈ V
19 ensym ⊢ C ≈ D → D ≈ C
20 endom ⊢ D ≈ C → D ≼ C
21 19 20 syl ⊢ C ≈ D → D ≼ C
22 xpdom2g ⊢ A ∈ V ∧ D ≼ C → A × D ≼ A × C
23 18 21 22 syl2an ⊢ A ≈ B ∧ C ≈ D → A × D ≼ A × C
24 domtr ⊢ B × D ≼ A × D ∧ A × D ≼ A × C → B × D ≼ A × C
25 17 23 24 syl2anc ⊢ A ≈ B ∧ C ≈ D → B × D ≼ A × C
26 sbth ⊢ A × C ≼ B × D ∧ B × D ≼ A × C → A × C ≈ B × D
27 11 25 26 syl2anc ⊢ A ≈ B ∧ C ≈ D → A × C ≈ B × D