Metamath Proof Explorer
Description: Equality deduction for Cartesian product. (Contributed by NM, 8-Dec-2013)
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|
Ref |
Expression |
|
Hypotheses |
xpeq1d.1 |
|
|
|
xpeq12d.2 |
|
|
Assertion |
xpeq12d |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
xpeq1d.1 |
|
| 2 |
|
xpeq12d.2 |
|
| 3 |
|
xpeq12 |
|
| 4 |
1 2 3
|
syl2anc |
|