Metamath Proof Explorer
Description: Equality deduction for Cartesian product. (Contributed by NM, 8-Dec-2013)
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Ref |
Expression |
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Hypotheses |
xpeq1d.1 |
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xpeq12d.2 |
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Assertion |
xpeq12d |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
xpeq1d.1 |
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2 |
|
xpeq12d.2 |
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3 |
|
xpeq12 |
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4 |
1 2 3
|
syl2anc |
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