Metamath Proof Explorer


Theorem xpexr2

Description: If a nonempty Cartesian product is a set, so are both of its components. (Contributed by NM, 27-Aug-2006)

Ref Expression
Assertion xpexr2 ⊢ A × B ∈ C ∧ A × B ≠ ∅ → A ∈ V ∧ B ∈ V

Proof

Step Hyp Ref Expression
1 xpnz ⊢ A ≠ ∅ ∧ B ≠ ∅ ↔ A × B ≠ ∅
2 dmxp ⊢ B ≠ ∅ → dom ⁡ A × B = A
3 2 adantl ⊢ A × B ∈ C ∧ B ≠ ∅ → dom ⁡ A × B = A
4 dmexg ⊢ A × B ∈ C → dom ⁡ A × B ∈ V
5 4 adantr ⊢ A × B ∈ C ∧ B ≠ ∅ → dom ⁡ A × B ∈ V
6 3 5 eqeltrrd ⊢ A × B ∈ C ∧ B ≠ ∅ → A ∈ V
7 rnxp ⊢ A ≠ ∅ → ran ⁡ A × B = B
8 7 adantl ⊢ A × B ∈ C ∧ A ≠ ∅ → ran ⁡ A × B = B
9 rnexg ⊢ A × B ∈ C → ran ⁡ A × B ∈ V
10 9 adantr ⊢ A × B ∈ C ∧ A ≠ ∅ → ran ⁡ A × B ∈ V
11 8 10 eqeltrrd ⊢ A × B ∈ C ∧ A ≠ ∅ → B ∈ V
12 6 11 anim12dan ⊢ A × B ∈ C ∧ B ≠ ∅ ∧ A ≠ ∅ → A ∈ V ∧ B ∈ V
13 12 ancom2s ⊢ A × B ∈ C ∧ A ≠ ∅ ∧ B ≠ ∅ → A ∈ V ∧ B ∈ V
14 1 13 sylan2br ⊢ A × B ∈ C ∧ A × B ≠ ∅ → A ∈ V ∧ B ∈ V