Metamath Proof Explorer


Theorem xppreima

Description: The preimage of a Cartesian product is the intersection of the preimages of each component function. (Contributed by Thierry Arnoux, 6-Jun-2017)

Ref Expression
Assertion xppreima ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V → F -1 Y × Z = 1 st ∘ F -1 Y ∩ 2 nd ∘ F -1 Z

Proof

Step Hyp Ref Expression
1 funfn ⊢ Fun ⁡ F ↔ F Fn dom ⁡ F
2 fncnvima2 ⊢ F Fn dom ⁡ F → F -1 Y × Z = x ∈ dom ⁡ F | F ⁡ x ∈ Y × Z
3 1 2 sylbi ⊢ Fun ⁡ F → F -1 Y × Z = x ∈ dom ⁡ F | F ⁡ x ∈ Y × Z
4 3 adantr ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V → F -1 Y × Z = x ∈ dom ⁡ F | F ⁡ x ∈ Y × Z
5 elxp6 ⊢ F ⁡ x ∈ Y × Z ↔ F ⁡ x = 1 st ⁡ F ⁡ x 2 nd ⁡ F ⁡ x ∧ 1 st ⁡ F ⁡ x ∈ Y ∧ 2 nd ⁡ F ⁡ x ∈ Z
6 fvco ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x = 1 st ⁡ F ⁡ x
7 fvco ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 2 nd ∘ F ⁡ x = 2 nd ⁡ F ⁡ x
8 6 7 opeq12d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x = 1 st ⁡ F ⁡ x 2 nd ⁡ F ⁡ x
9 8 eqeq2d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x ↔ F ⁡ x = 1 st ⁡ F ⁡ x 2 nd ⁡ F ⁡ x
10 6 eleq1d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ↔ 1 st ⁡ F ⁡ x ∈ Y
11 7 eleq1d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 2 nd ∘ F ⁡ x ∈ Z ↔ 2 nd ⁡ F ⁡ x ∈ Z
12 10 11 anbi12d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z ↔ 1 st ⁡ F ⁡ x ∈ Y ∧ 2 nd ⁡ F ⁡ x ∈ Z
13 9 12 anbi12d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x ∧ 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z ↔ F ⁡ x = 1 st ⁡ F ⁡ x 2 nd ⁡ F ⁡ x ∧ 1 st ⁡ F ⁡ x ∈ Y ∧ 2 nd ⁡ F ⁡ x ∈ Z
14 5 13 bitr4id ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → F ⁡ x ∈ Y × Z ↔ F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x ∧ 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z
15 14 adantlr ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V ∧ x ∈ dom ⁡ F → F ⁡ x ∈ Y × Z ↔ F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x ∧ 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z
16 opfv ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V ∧ x ∈ dom ⁡ F → F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x
17 16 biantrurd ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z ↔ F ⁡ x = 1 st ∘ F ⁡ x 2 nd ∘ F ⁡ x ∧ 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z
18 fo1st ⊢ 1 st : V ⟶ onto V
19 fofun ⊢ 1 st : V ⟶ onto V → Fun ⁡ 1 st
20 18 19 ax-mp ⊢ Fun ⁡ 1 st
21 funco ⊢ Fun ⁡ 1 st ∧ Fun ⁡ F → Fun ⁡ 1 st ∘ F
22 20 21 mpan ⊢ Fun ⁡ F → Fun ⁡ 1 st ∘ F
23 22 adantr ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → Fun ⁡ 1 st ∘ F
24 ssv ⊢ F dom ⁡ F ⊆ V
25 fof ⊢ 1 st : V ⟶ onto V → 1 st : V ⟶ V
26 fdm ⊢ 1 st : V ⟶ V → dom ⁡ 1 st = V
27 18 25 26 mp2b ⊢ dom ⁡ 1 st = V
28 24 27 sseqtrri ⊢ F dom ⁡ F ⊆ dom ⁡ 1 st
29 ssid ⊢ dom ⁡ F ⊆ dom ⁡ F
30 funimass3 ⊢ Fun ⁡ F ∧ dom ⁡ F ⊆ dom ⁡ F → F dom ⁡ F ⊆ dom ⁡ 1 st ↔ dom ⁡ F ⊆ F -1 dom ⁡ 1 st
31 29 30 mpan2 ⊢ Fun ⁡ F → F dom ⁡ F ⊆ dom ⁡ 1 st ↔ dom ⁡ F ⊆ F -1 dom ⁡ 1 st
32 28 31 mpbii ⊢ Fun ⁡ F → dom ⁡ F ⊆ F -1 dom ⁡ 1 st
33 32 sselda ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → x ∈ F -1 dom ⁡ 1 st
34 dmco ⊢ dom ⁡ 1 st ∘ F = F -1 dom ⁡ 1 st
35 33 34 eleqtrrdi ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → x ∈ dom ⁡ 1 st ∘ F
36 fvimacnv ⊢ Fun ⁡ 1 st ∘ F ∧ x ∈ dom ⁡ 1 st ∘ F → 1 st ∘ F ⁡ x ∈ Y ↔ x ∈ 1 st ∘ F -1 Y
37 23 35 36 syl2anc ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ↔ x ∈ 1 st ∘ F -1 Y
38 fo2nd ⊢ 2 nd : V ⟶ onto V
39 fofun ⊢ 2 nd : V ⟶ onto V → Fun ⁡ 2 nd
40 38 39 ax-mp ⊢ Fun ⁡ 2 nd
41 funco ⊢ Fun ⁡ 2 nd ∧ Fun ⁡ F → Fun ⁡ 2 nd ∘ F
42 40 41 mpan ⊢ Fun ⁡ F → Fun ⁡ 2 nd ∘ F
43 42 adantr ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → Fun ⁡ 2 nd ∘ F
44 fof ⊢ 2 nd : V ⟶ onto V → 2 nd : V ⟶ V
45 fdm ⊢ 2 nd : V ⟶ V → dom ⁡ 2 nd = V
46 38 44 45 mp2b ⊢ dom ⁡ 2 nd = V
47 24 46 sseqtrri ⊢ F dom ⁡ F ⊆ dom ⁡ 2 nd
48 funimass3 ⊢ Fun ⁡ F ∧ dom ⁡ F ⊆ dom ⁡ F → F dom ⁡ F ⊆ dom ⁡ 2 nd ↔ dom ⁡ F ⊆ F -1 dom ⁡ 2 nd
49 29 48 mpan2 ⊢ Fun ⁡ F → F dom ⁡ F ⊆ dom ⁡ 2 nd ↔ dom ⁡ F ⊆ F -1 dom ⁡ 2 nd
50 47 49 mpbii ⊢ Fun ⁡ F → dom ⁡ F ⊆ F -1 dom ⁡ 2 nd
51 50 sselda ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → x ∈ F -1 dom ⁡ 2 nd
52 dmco ⊢ dom ⁡ 2 nd ∘ F = F -1 dom ⁡ 2 nd
53 51 52 eleqtrrdi ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → x ∈ dom ⁡ 2 nd ∘ F
54 fvimacnv ⊢ Fun ⁡ 2 nd ∘ F ∧ x ∈ dom ⁡ 2 nd ∘ F → 2 nd ∘ F ⁡ x ∈ Z ↔ x ∈ 2 nd ∘ F -1 Z
55 43 53 54 syl2anc ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 2 nd ∘ F ⁡ x ∈ Z ↔ x ∈ 2 nd ∘ F -1 Z
56 37 55 anbi12d ⊢ Fun ⁡ F ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z ↔ x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
57 56 adantlr ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V ∧ x ∈ dom ⁡ F → 1 st ∘ F ⁡ x ∈ Y ∧ 2 nd ∘ F ⁡ x ∈ Z ↔ x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
58 15 17 57 3bitr2d ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V ∧ x ∈ dom ⁡ F → F ⁡ x ∈ Y × Z ↔ x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
59 58 rabbidva ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V → x ∈ dom ⁡ F | F ⁡ x ∈ Y × Z = x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
60 4 59 eqtrd ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V → F -1 Y × Z = x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
61 dfin5 ⊢ dom ⁡ F ∩ 1 st ∘ F -1 Y = x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y
62 dfin5 ⊢ dom ⁡ F ∩ 2 nd ∘ F -1 Z = x ∈ dom ⁡ F | x ∈ 2 nd ∘ F -1 Z
63 61 62 ineq12i ⊢ dom ⁡ F ∩ 1 st ∘ F -1 Y ∩ dom ⁡ F ∩ 2 nd ∘ F -1 Z = x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∩ x ∈ dom ⁡ F | x ∈ 2 nd ∘ F -1 Z
64 cnvimass ⊢ 1 st ∘ F -1 Y ⊆ dom ⁡ 1 st ∘ F
65 dmcoss ⊢ dom ⁡ 1 st ∘ F ⊆ dom ⁡ F
66 64 65 sstri ⊢ 1 st ∘ F -1 Y ⊆ dom ⁡ F
67 sseqin2 ⊢ 1 st ∘ F -1 Y ⊆ dom ⁡ F ↔ dom ⁡ F ∩ 1 st ∘ F -1 Y = 1 st ∘ F -1 Y
68 66 67 mpbi ⊢ dom ⁡ F ∩ 1 st ∘ F -1 Y = 1 st ∘ F -1 Y
69 cnvimass ⊢ 2 nd ∘ F -1 Z ⊆ dom ⁡ 2 nd ∘ F
70 dmcoss ⊢ dom ⁡ 2 nd ∘ F ⊆ dom ⁡ F
71 69 70 sstri ⊢ 2 nd ∘ F -1 Z ⊆ dom ⁡ F
72 sseqin2 ⊢ 2 nd ∘ F -1 Z ⊆ dom ⁡ F ↔ dom ⁡ F ∩ 2 nd ∘ F -1 Z = 2 nd ∘ F -1 Z
73 71 72 mpbi ⊢ dom ⁡ F ∩ 2 nd ∘ F -1 Z = 2 nd ∘ F -1 Z
74 68 73 ineq12i ⊢ dom ⁡ F ∩ 1 st ∘ F -1 Y ∩ dom ⁡ F ∩ 2 nd ∘ F -1 Z = 1 st ∘ F -1 Y ∩ 2 nd ∘ F -1 Z
75 inrab ⊢ x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∩ x ∈ dom ⁡ F | x ∈ 2 nd ∘ F -1 Z = x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z
76 63 74 75 3eqtr3ri ⊢ x ∈ dom ⁡ F | x ∈ 1 st ∘ F -1 Y ∧ x ∈ 2 nd ∘ F -1 Z = 1 st ∘ F -1 Y ∩ 2 nd ∘ F -1 Z
77 60 76 eqtrdi ⊢ Fun ⁡ F ∧ ran ⁡ F ⊆ V × V → F -1 Y × Z = 1 st ∘ F -1 Y ∩ 2 nd ∘ F -1 Z