Metamath Proof Explorer


Theorem xppreima2

Description: The preimage of a Cartesian product is the intersection of the preimages of each component function. (Contributed by Thierry Arnoux, 7-Jun-2017)

Ref Expression
Hypotheses xppreima2.1 ⊢ φ → F : A ⟶ B
xppreima2.2 ⊢ φ → G : A ⟶ C
xppreima2.3 ⊢ H = x ∈ A ⟼ F ⁡ x G ⁡ x
Assertion xppreima2 ⊢ φ → H -1 Y × Z = F -1 Y ∩ G -1 Z

Proof

Step Hyp Ref Expression
1 xppreima2.1 ⊢ φ → F : A ⟶ B
2 xppreima2.2 ⊢ φ → G : A ⟶ C
3 xppreima2.3 ⊢ H = x ∈ A ⟼ F ⁡ x G ⁡ x
4 3 funmpt2 ⊢ Fun ⁡ H
5 1 ffvelcdmda ⊢ φ ∧ x ∈ A → F ⁡ x ∈ B
6 2 ffvelcdmda ⊢ φ ∧ x ∈ A → G ⁡ x ∈ C
7 opelxp ⊢ F ⁡ x G ⁡ x ∈ B × C ↔ F ⁡ x ∈ B ∧ G ⁡ x ∈ C
8 5 6 7 sylanbrc ⊢ φ ∧ x ∈ A → F ⁡ x G ⁡ x ∈ B × C
9 8 3 fmptd ⊢ φ → H : A ⟶ B × C
10 9 frnd ⊢ φ → ran ⁡ H ⊆ B × C
11 xpss ⊢ B × C ⊆ V × V
12 10 11 sstrdi ⊢ φ → ran ⁡ H ⊆ V × V
13 xppreima ⊢ Fun ⁡ H ∧ ran ⁡ H ⊆ V × V → H -1 Y × Z = 1 st ∘ H -1 Y ∩ 2 nd ∘ H -1 Z
14 4 12 13 sylancr ⊢ φ → H -1 Y × Z = 1 st ∘ H -1 Y ∩ 2 nd ∘ H -1 Z
15 fo1st ⊢ 1 st : V ⟶ onto V
16 fofn ⊢ 1 st : V ⟶ onto V → 1 st Fn V
17 15 16 ax-mp ⊢ 1 st Fn V
18 opex ⊢ F ⁡ x G ⁡ x ∈ V
19 18 3 fnmpti ⊢ H Fn A
20 ssv ⊢ ran ⁡ H ⊆ V
21 fnco ⊢ 1 st Fn V ∧ H Fn A ∧ ran ⁡ H ⊆ V → 1 st ∘ H Fn A
22 17 19 20 21 mp3an ⊢ 1 st ∘ H Fn A
23 22 a1i ⊢ φ → 1 st ∘ H Fn A
24 1 ffnd ⊢ φ → F Fn A
25 4 a1i ⊢ φ ∧ x ∈ A → Fun ⁡ H
26 12 adantr ⊢ φ ∧ x ∈ A → ran ⁡ H ⊆ V × V
27 simpr ⊢ φ ∧ x ∈ A → x ∈ A
28 18 3 dmmpti ⊢ dom ⁡ H = A
29 27 28 eleqtrrdi ⊢ φ ∧ x ∈ A → x ∈ dom ⁡ H
30 opfv ⊢ Fun ⁡ H ∧ ran ⁡ H ⊆ V × V ∧ x ∈ dom ⁡ H → H ⁡ x = 1 st ∘ H ⁡ x 2 nd ∘ H ⁡ x
31 25 26 29 30 syl21anc ⊢ φ ∧ x ∈ A → H ⁡ x = 1 st ∘ H ⁡ x 2 nd ∘ H ⁡ x
32 3 fvmpt2 ⊢ x ∈ A ∧ F ⁡ x G ⁡ x ∈ B × C → H ⁡ x = F ⁡ x G ⁡ x
33 27 8 32 syl2anc ⊢ φ ∧ x ∈ A → H ⁡ x = F ⁡ x G ⁡ x
34 31 33 eqtr3d ⊢ φ ∧ x ∈ A → 1 st ∘ H ⁡ x 2 nd ∘ H ⁡ x = F ⁡ x G ⁡ x
35 fvex ⊢ 1 st ∘ H ⁡ x ∈ V
36 fvex ⊢ 2 nd ∘ H ⁡ x ∈ V
37 35 36 opth ⊢ 1 st ∘ H ⁡ x 2 nd ∘ H ⁡ x = F ⁡ x G ⁡ x ↔ 1 st ∘ H ⁡ x = F ⁡ x ∧ 2 nd ∘ H ⁡ x = G ⁡ x
38 34 37 sylib ⊢ φ ∧ x ∈ A → 1 st ∘ H ⁡ x = F ⁡ x ∧ 2 nd ∘ H ⁡ x = G ⁡ x
39 38 simpld ⊢ φ ∧ x ∈ A → 1 st ∘ H ⁡ x = F ⁡ x
40 23 24 39 eqfnfvd ⊢ φ → 1 st ∘ H = F
41 40 cnveqd ⊢ φ → 1 st ∘ H -1 = F -1
42 41 imaeq1d ⊢ φ → 1 st ∘ H -1 Y = F -1 Y
43 fo2nd ⊢ 2 nd : V ⟶ onto V
44 fofn ⊢ 2 nd : V ⟶ onto V → 2 nd Fn V
45 43 44 ax-mp ⊢ 2 nd Fn V
46 fnco ⊢ 2 nd Fn V ∧ H Fn A ∧ ran ⁡ H ⊆ V → 2 nd ∘ H Fn A
47 45 19 20 46 mp3an ⊢ 2 nd ∘ H Fn A
48 47 a1i ⊢ φ → 2 nd ∘ H Fn A
49 2 ffnd ⊢ φ → G Fn A
50 38 simprd ⊢ φ ∧ x ∈ A → 2 nd ∘ H ⁡ x = G ⁡ x
51 48 49 50 eqfnfvd ⊢ φ → 2 nd ∘ H = G
52 51 cnveqd ⊢ φ → 2 nd ∘ H -1 = G -1
53 52 imaeq1d ⊢ φ → 2 nd ∘ H -1 Z = G -1 Z
54 42 53 ineq12d ⊢ φ → 1 st ∘ H -1 Y ∩ 2 nd ∘ H -1 Z = F -1 Y ∩ G -1 Z
55 14 54 eqtrd ⊢ φ → H -1 Y × Z = F -1 Y ∩ G -1 Z