Metamath Proof Explorer


Theorem xrecex

Description: Existence of reciprocal of nonzero real number. (Contributed by Thierry Arnoux, 17-Dec-2016)

Ref Expression
Assertion xrecex ⊢ A ∈ ℝ ∧ A ≠ 0 → ∃ x ∈ ℝ A ⋅ 𝑒 x = 1

Proof

Step Hyp Ref Expression
1 ax-rrecex ⊢ A ∈ ℝ ∧ A ≠ 0 → ∃ x ∈ ℝ A ⁢ x = 1
2 rexmul ⊢ A ∈ ℝ ∧ x ∈ ℝ → A ⋅ 𝑒 x = A ⁢ x
3 2 eqeq1d ⊢ A ∈ ℝ ∧ x ∈ ℝ → A ⋅ 𝑒 x = 1 ↔ A ⁢ x = 1
4 3 ex ⊢ A ∈ ℝ → x ∈ ℝ → A ⋅ 𝑒 x = 1 ↔ A ⁢ x = 1
5 4 adantr ⊢ A ∈ ℝ ∧ A ≠ 0 → x ∈ ℝ → A ⋅ 𝑒 x = 1 ↔ A ⁢ x = 1
6 5 pm5.32d ⊢ A ∈ ℝ ∧ A ≠ 0 → x ∈ ℝ ∧ A ⋅ 𝑒 x = 1 ↔ x ∈ ℝ ∧ A ⁢ x = 1
7 6 rexbidv2 ⊢ A ∈ ℝ ∧ A ≠ 0 → ∃ x ∈ ℝ A ⋅ 𝑒 x = 1 ↔ ∃ x ∈ ℝ A ⁢ x = 1
8 1 7 mpbird ⊢ A ∈ ℝ ∧ A ≠ 0 → ∃ x ∈ ℝ A ⋅ 𝑒 x = 1