Metamath Proof Explorer


Theorem zconstr

Description: Integers are constructible. (Contributed by Thierry Arnoux, 3-Nov-2025)

Ref Expression
Hypothesis zconstr.1 ⊢ φ → X ∈ ℤ
Assertion zconstr ⊢ φ → X ∈ Constr

Proof

Step Hyp Ref Expression
1 zconstr.1 ⊢ φ → X ∈ ℤ
2 simpr ⊢ φ ∧ X ∈ ℕ 0 → X ∈ ℕ 0
3 2 nn0constr ⊢ φ ∧ X ∈ ℕ 0 → X ∈ Constr
4 1 zcnd ⊢ φ → X ∈ ℂ
5 4 negnegd ⊢ φ → − − X = X
6 5 adantr ⊢ φ ∧ − X ∈ ℕ 0 → − − X = X
7 simpr ⊢ φ ∧ − X ∈ ℕ 0 → − X ∈ ℕ 0
8 7 nn0constr ⊢ φ ∧ − X ∈ ℕ 0 → − X ∈ Constr
9 8 constrnegcl ⊢ φ ∧ − X ∈ ℕ 0 → − − X ∈ Constr
10 6 9 eqeltrrd ⊢ φ ∧ − X ∈ ℕ 0 → X ∈ Constr
11 elznn0 ⊢ X ∈ ℤ ↔ X ∈ ℝ ∧ X ∈ ℕ 0 ∨ − X ∈ ℕ 0
12 1 11 sylib ⊢ φ → X ∈ ℝ ∧ X ∈ ℕ 0 ∨ − X ∈ ℕ 0
13 12 simprd ⊢ φ → X ∈ ℕ 0 ∨ − X ∈ ℕ 0
14 3 10 13 mpjaodan ⊢ φ → X ∈ Constr