Metamath Proof Explorer


Theorem znlidl

Description: The set n ZZ is an ideal in ZZ . (Contributed by Mario Carneiro, 14-Jun-2015) (Revised by AV, 13-Jun-2019)

Ref Expression
Hypothesis znval.s ⊢ S = RSpan ⁡ ℤ ring
Assertion znlidl ⊢ N ∈ ℤ → S ⁡ N ∈ LIdeal ⁡ ℤ ring

Proof

Step Hyp Ref Expression
1 znval.s ⊢ S = RSpan ⁡ ℤ ring
2 zringring ⊢ ℤ ring ∈ Ring
3 snssi ⊢ N ∈ ℤ → N ⊆ ℤ
4 zringbas ⊢ ℤ = Base ℤ ring
5 eqid ⊢ LIdeal ⁡ ℤ ring = LIdeal ⁡ ℤ ring
6 1 4 5 rspcl ⊢ ℤ ring ∈ Ring ∧ N ⊆ ℤ → S ⁡ N ∈ LIdeal ⁡ ℤ ring
7 2 3 6 sylancr ⊢ N ∈ ℤ → S ⁡ N ∈ LIdeal ⁡ ℤ ring