Metamath Proof Explorer


Theorem znzrhfo

Description: The ZZ ring homomorphism is a surjection onto Z/nZ . (Contributed by Mario Carneiro, 15-Jun-2015)

Ref Expression
Hypotheses znzrhfo.y ⊢ Y = ℤ/Nℤ
znzrhfo.b ⊢ B = Base Y
znzrhfo.2 ⊢ L = ℤRHom ⁡ Y
Assertion znzrhfo ⊢ N ∈ ℕ 0 → L : ℤ ⟶ onto B

Proof

Step Hyp Ref Expression
1 znzrhfo.y ⊢ Y = ℤ/Nℤ
2 znzrhfo.b ⊢ B = Base Y
3 znzrhfo.2 ⊢ L = ℤRHom ⁡ Y
4 eqidd ⊢ N ∈ ℕ 0 → ℤ ring / 𝑠 ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = ℤ ring / 𝑠 ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N
5 zringbas ⊢ ℤ = Base ℤ ring
6 5 a1i ⊢ N ∈ ℕ 0 → ℤ = Base ℤ ring
7 eqid ⊢ x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N
8 ovexd ⊢ N ∈ ℕ 0 → ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N ∈ V
9 zringring ⊢ ℤ ring ∈ Ring
10 9 a1i ⊢ N ∈ ℕ 0 → ℤ ring ∈ Ring
11 4 6 7 8 10 quslem ⊢ N ∈ ℕ 0 → x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N
12 eqid ⊢ RSpan ⁡ ℤ ring = RSpan ⁡ ℤ ring
13 eqid ⊢ ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N
14 12 1 13 znbas ⊢ N ∈ ℕ 0 → ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = Base Y
15 14 2 eqtr4di ⊢ N ∈ ℕ 0 → ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = B
16 foeq3 ⊢ ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N = B → x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N ↔ x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto B
17 15 16 syl ⊢ N ∈ ℕ 0 → x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto ℤ / ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N ↔ x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto B
18 11 17 mpbid ⊢ N ∈ ℕ 0 → x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto B
19 12 13 1 3 znzrh2 ⊢ N ∈ ℕ 0 → L = x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N
20 foeq1 ⊢ L = x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N → L : ℤ ⟶ onto B ↔ x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto B
21 19 20 syl ⊢ N ∈ ℕ 0 → L : ℤ ⟶ onto B ↔ x ∈ ℤ ⟼ x ℤ ring ~ QG RSpan ⁡ ℤ ring ⁡ N : ℤ ⟶ onto B
22 18 21 mpbird ⊢ N ∈ ℕ 0 → L : ℤ ⟶ onto B