Metamath Proof Explorer


Theorem 0pos

Description: Technical lemma to simplify the statement of ipopos . The empty set is (rather pathologically) a poset under our definitions, since it has an empty base set ( str0 ) and any relation partially orders an empty set. (Contributed by Stefan O'Rear, 30-Jan-2015) (Proof shortened by AV, 13-Oct-2024)

Ref Expression
Assertion 0pos ∅ ∈ Poset

Proof

Step Hyp Ref Expression
1 0ex ∅ ∈ V
2 ral0 𝑎 ∈ ∅ ∀ 𝑏 ∈ ∅ ∀ 𝑐 ∈ ∅ ( 𝑎𝑎 ∧ ( ( 𝑎𝑏𝑏𝑎 ) → 𝑎 = 𝑏 ) ∧ ( ( 𝑎𝑏𝑏𝑐 ) → 𝑎𝑐 ) )
3 base0 ∅ = ( Base ‘ ∅ )
4 pleid le = Slot ( le ‘ ndx )
5 4 str0 ∅ = ( le ‘ ∅ )
6 3 5 ispos ( ∅ ∈ Poset ↔ ( ∅ ∈ V ∧ ∀ 𝑎 ∈ ∅ ∀ 𝑏 ∈ ∅ ∀ 𝑐 ∈ ∅ ( 𝑎𝑎 ∧ ( ( 𝑎𝑏𝑏𝑎 ) → 𝑎 = 𝑏 ) ∧ ( ( 𝑎𝑏𝑏𝑐 ) → 𝑎𝑐 ) ) ) )
7 1 2 6 mpbir2an ∅ ∈ Poset