Metamath Proof Explorer


Theorem 0vfval

Description: Value of the function for the zero vector on a normed complex vector space. (Contributed by NM, 24-Apr-2007) (Revised by Mario Carneiro, 21-Dec-2013) (New usage is discouraged.)

Ref Expression
Hypotheses 0vfval.2 𝐺 = ( +𝑣𝑈 )
0vfval.5 𝑍 = ( 0vec𝑈 )
Assertion 0vfval ( 𝑈𝑉𝑍 = ( GId ‘ 𝐺 ) )

Proof

Step Hyp Ref Expression
1 0vfval.2 𝐺 = ( +𝑣𝑈 )
2 0vfval.5 𝑍 = ( 0vec𝑈 )
3 elex ( 𝑈𝑉𝑈 ∈ V )
4 fo1st 1st : V –onto→ V
5 fofn ( 1st : V –onto→ V → 1st Fn V )
6 4 5 ax-mp 1st Fn V
7 ssv ran 1st ⊆ V
8 fnco ( ( 1st Fn V ∧ 1st Fn V ∧ ran 1st ⊆ V ) → ( 1st ∘ 1st ) Fn V )
9 6 6 7 8 mp3an ( 1st ∘ 1st ) Fn V
10 df-va +𝑣 = ( 1st ∘ 1st )
11 10 fneq1i ( +𝑣 Fn V ↔ ( 1st ∘ 1st ) Fn V )
12 9 11 mpbir +𝑣 Fn V
13 fvco2 ( ( +𝑣 Fn V ∧ 𝑈 ∈ V ) → ( ( GId ∘ +𝑣 ) ‘ 𝑈 ) = ( GId ‘ ( +𝑣𝑈 ) ) )
14 12 13 mpan ( 𝑈 ∈ V → ( ( GId ∘ +𝑣 ) ‘ 𝑈 ) = ( GId ‘ ( +𝑣𝑈 ) ) )
15 df-0v 0vec = ( GId ∘ +𝑣 )
16 15 fveq1i ( 0vec𝑈 ) = ( ( GId ∘ +𝑣 ) ‘ 𝑈 )
17 2 16 eqtri 𝑍 = ( ( GId ∘ +𝑣 ) ‘ 𝑈 )
18 1 fveq2i ( GId ‘ 𝐺 ) = ( GId ‘ ( +𝑣𝑈 ) )
19 14 17 18 3eqtr4g ( 𝑈 ∈ V → 𝑍 = ( GId ‘ 𝐺 ) )
20 3 19 syl ( 𝑈𝑉𝑍 = ( GId ‘ 𝐺 ) )