Metamath Proof Explorer


Theorem 19.27v

Description: Version of 19.27 with a disjoint variable condition, requiring fewer axioms. (Contributed by NM, 3-Jun-2004)

Ref Expression
Assertion 19.27v ( ∀ 𝑥 ( 𝜑𝜓 ) ↔ ( ∀ 𝑥 𝜑𝜓 ) )

Proof

Step Hyp Ref Expression
1 19.26 ( ∀ 𝑥 ( 𝜑𝜓 ) ↔ ( ∀ 𝑥 𝜑 ∧ ∀ 𝑥 𝜓 ) )
2 19.3v ( ∀ 𝑥 𝜓𝜓 )
3 2 anbi2i ( ( ∀ 𝑥 𝜑 ∧ ∀ 𝑥 𝜓 ) ↔ ( ∀ 𝑥 𝜑𝜓 ) )
4 1 3 bitri ( ∀ 𝑥 ( 𝜑𝜓 ) ↔ ( ∀ 𝑥 𝜑𝜓 ) )