Metamath Proof Explorer


Theorem 2exnaln

Description: Theorem *11.22 in WhiteheadRussell p. 160. (Contributed by Andrew Salmon, 24-May-2011)

Ref Expression
Assertion 2exnaln ( ∃ 𝑥 ∃ 𝑦 𝜑 ↔ ¬ ∀ 𝑥 ∀ 𝑦 ¬ 𝜑 )

Proof

Step Hyp Ref Expression
1 df-ex ⊢ ( ∃ 𝑥 ∃ 𝑦 𝜑 ↔ ¬ ∀ 𝑥 ¬ ∃ 𝑦 𝜑 )
2 alnex ⊢ ( ∀ 𝑦 ¬ 𝜑 ↔ ¬ ∃ 𝑦 𝜑 )
3 2 albii ⊢ ( ∀ 𝑥 ∀ 𝑦 ¬ 𝜑 ↔ ∀ 𝑥 ¬ ∃ 𝑦 𝜑 )
4 1 3 xchbinxr ⊢ ( ∃ 𝑥 ∃ 𝑦 𝜑 ↔ ¬ ∀ 𝑥 ∀ 𝑦 ¬ 𝜑 )