Metamath Proof Explorer


Theorem 2fcoidinvd

Description: Show that a function is the inverse of a function if their compositions are the identity functions. (Contributed by Mario Carneiro, 21-Mar-2015) (Revised by AV, 15-Dec-2019)

Ref Expression
Hypotheses fcof1od.f ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
fcof1od.g ⊢ ( 𝜑 → 𝐺 : 𝐵 ⟶ 𝐴 )
fcof1od.a ⊢ ( 𝜑 → ( 𝐺 ∘ 𝐹 ) = ( I ↾ 𝐴 ) )
fcof1od.b ⊢ ( 𝜑 → ( 𝐹 ∘ 𝐺 ) = ( I ↾ 𝐵 ) )
Assertion 2fcoidinvd ( 𝜑 → ◡ 𝐹 = 𝐺 )

Proof

Step Hyp Ref Expression
1 fcof1od.f ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
2 fcof1od.g ⊢ ( 𝜑 → 𝐺 : 𝐵 ⟶ 𝐴 )
3 fcof1od.a ⊢ ( 𝜑 → ( 𝐺 ∘ 𝐹 ) = ( I ↾ 𝐴 ) )
4 fcof1od.b ⊢ ( 𝜑 → ( 𝐹 ∘ 𝐺 ) = ( I ↾ 𝐵 ) )
5 1 2 3 4 fcof1od ⊢ ( 𝜑 → 𝐹 : 𝐴 –1-1-onto→ 𝐵 )
6 5 2 4 fcof1oinvd ⊢ ( 𝜑 → ◡ 𝐹 = 𝐺 )