Metamath Proof Explorer


Theorem 2sqlem1

Description: Lemma for 2sq . (Contributed by Mario Carneiro, 19-Jun-2015)

Ref Expression
Hypothesis 2sq.1 ⊢ 𝑆 = ran ( 𝑤 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑤 ) ↑ 2 ) )
Assertion 2sqlem1 ( 𝐴 ∈ 𝑆 ↔ ∃ 𝑥 ∈ ℤ[i] 𝐴 = ( ( abs ‘ 𝑥 ) ↑ 2 ) )

Proof

Step Hyp Ref Expression
1 2sq.1 ⊢ 𝑆 = ran ( 𝑤 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑤 ) ↑ 2 ) )
2 1 eleq2i ⊢ ( 𝐴 ∈ 𝑆 ↔ 𝐴 ∈ ran ( 𝑤 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑤 ) ↑ 2 ) ) )
3 fveq2 ⊢ ( 𝑤 = 𝑥 → ( abs ‘ 𝑤 ) = ( abs ‘ 𝑥 ) )
4 3 oveq1d ⊢ ( 𝑤 = 𝑥 → ( ( abs ‘ 𝑤 ) ↑ 2 ) = ( ( abs ‘ 𝑥 ) ↑ 2 ) )
5 4 cbvmptv ⊢ ( 𝑤 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑤 ) ↑ 2 ) ) = ( 𝑥 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑥 ) ↑ 2 ) )
6 ovex ⊢ ( ( abs ‘ 𝑥 ) ↑ 2 ) ∈ V
7 5 6 elrnmpti ⊢ ( 𝐴 ∈ ran ( 𝑤 ∈ ℤ[i] ↦ ( ( abs ‘ 𝑤 ) ↑ 2 ) ) ↔ ∃ 𝑥 ∈ ℤ[i] 𝐴 = ( ( abs ‘ 𝑥 ) ↑ 2 ) )
8 2 7 bitri ⊢ ( 𝐴 ∈ 𝑆 ↔ ∃ 𝑥 ∈ ℤ[i] 𝐴 = ( ( abs ‘ 𝑥 ) ↑ 2 ) )