Metamath Proof Explorer
Description: Remove a hypothesis from the second member of a biconditional.
(Contributed by FL, 22-Jul-2008)
|
|
Ref |
Expression |
|
Hypothesis |
3anibar.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( 𝜃 ↔ ( 𝜒 ∧ 𝜏 ) ) ) |
|
Assertion |
3anibar |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( 𝜃 ↔ 𝜏 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3anibar.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( 𝜃 ↔ ( 𝜒 ∧ 𝜏 ) ) ) |
2 |
|
simp3 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜒 ) |
3 |
2 1
|
mpbirand |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( 𝜃 ↔ 𝜏 ) ) |