Metamath Proof Explorer
Description: An elimination deduction. (Contributed by Alan Sare, 17-Oct-2017)
(Proof shortened by Wolf Lammen, 13-Apr-2022)
|
|
Ref |
Expression |
|
Hypotheses |
3imp3i2an.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
|
|
3imp3i2an.2 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜏 ) |
|
|
3imp3i2an.3 |
⊢ ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) |
|
Assertion |
3imp3i2an |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜂 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3imp3i2an.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
2 |
|
3imp3i2an.2 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜏 ) |
3 |
|
3imp3i2an.3 |
⊢ ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) |
4 |
2
|
3adant2 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜏 ) |
5 |
1 4 3
|
syl2anc |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜂 ) |