Metamath Proof Explorer


Theorem 3jaao

Description: Inference conjoining and disjoining the antecedents of three implications. (Contributed by Jeff Hankins, 15-Aug-2009) (Proof shortened by Andrew Salmon, 13-May-2011) (Proof shortened by Garrett Katz, 16-Jun-2026)

Ref Expression
Hypotheses 3jaao.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
3jaao.2 ⊢ ( 𝜃 → ( 𝜏 → 𝜒 ) )
3jaao.3 ⊢ ( 𝜂 → ( 𝜁 → 𝜒 ) )
Assertion 3jaao ( ( 𝜑 ∧ 𝜃 ∧ 𝜂 ) → ( ( 𝜓 ∨ 𝜏 ∨ 𝜁 ) → 𝜒 ) )

Proof

Step Hyp Ref Expression
1 3jaao.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
2 3jaao.2 ⊢ ( 𝜃 → ( 𝜏 → 𝜒 ) )
3 3jaao.3 ⊢ ( 𝜂 → ( 𝜁 → 𝜒 ) )
4 3jao ⊢ ( ( ( 𝜓 → 𝜒 ) ∧ ( 𝜏 → 𝜒 ) ∧ ( 𝜁 → 𝜒 ) ) → ( ( 𝜓 ∨ 𝜏 ∨ 𝜁 ) → 𝜒 ) )
5 1 2 3 4 syl3an ⊢ ( ( 𝜑 ∧ 𝜃 ∧ 𝜂 ) → ( ( 𝜓 ∨ 𝜏 ∨ 𝜁 ) → 𝜒 ) )