Metamath Proof Explorer
Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 14-Jun-2012)
|
|
Ref |
Expression |
|
Hypotheses |
3netr4g.1 |
⊢ ( 𝜑 → 𝐴 ≠ 𝐵 ) |
|
|
3netr4g.2 |
⊢ 𝐶 = 𝐴 |
|
|
3netr4g.3 |
⊢ 𝐷 = 𝐵 |
|
Assertion |
3netr4g |
⊢ ( 𝜑 → 𝐶 ≠ 𝐷 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3netr4g.1 |
⊢ ( 𝜑 → 𝐴 ≠ 𝐵 ) |
2 |
|
3netr4g.2 |
⊢ 𝐶 = 𝐴 |
3 |
|
3netr4g.3 |
⊢ 𝐷 = 𝐵 |
4 |
2 3
|
neeq12i |
⊢ ( 𝐶 ≠ 𝐷 ↔ 𝐴 ≠ 𝐵 ) |
5 |
1 4
|
sylibr |
⊢ ( 𝜑 → 𝐶 ≠ 𝐷 ) |