Description: Join 3 biconditionals with disjunction. (Contributed by NM, 17-May-1994)
Ref | Expression | ||
---|---|---|---|
Hypotheses | bi3.1 | ⊢ ( 𝜑 ↔ 𝜓 ) | |
bi3.2 | ⊢ ( 𝜒 ↔ 𝜃 ) | ||
bi3.3 | ⊢ ( 𝜏 ↔ 𝜂 ) | ||
Assertion | 3orbi123i | ⊢ ( ( 𝜑 ∨ 𝜒 ∨ 𝜏 ) ↔ ( 𝜓 ∨ 𝜃 ∨ 𝜂 ) ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | bi3.1 | ⊢ ( 𝜑 ↔ 𝜓 ) | |
2 | bi3.2 | ⊢ ( 𝜒 ↔ 𝜃 ) | |
3 | bi3.3 | ⊢ ( 𝜏 ↔ 𝜂 ) | |
4 | 1 2 | orbi12i | ⊢ ( ( 𝜑 ∨ 𝜒 ) ↔ ( 𝜓 ∨ 𝜃 ) ) |
5 | 4 3 | orbi12i | ⊢ ( ( ( 𝜑 ∨ 𝜒 ) ∨ 𝜏 ) ↔ ( ( 𝜓 ∨ 𝜃 ) ∨ 𝜂 ) ) |
6 | df-3or | ⊢ ( ( 𝜑 ∨ 𝜒 ∨ 𝜏 ) ↔ ( ( 𝜑 ∨ 𝜒 ) ∨ 𝜏 ) ) | |
7 | df-3or | ⊢ ( ( 𝜓 ∨ 𝜃 ∨ 𝜂 ) ↔ ( ( 𝜓 ∨ 𝜃 ) ∨ 𝜂 ) ) | |
8 | 5 6 7 | 3bitr4i | ⊢ ( ( 𝜑 ∨ 𝜒 ∨ 𝜏 ) ↔ ( 𝜓 ∨ 𝜃 ∨ 𝜂 ) ) |