Metamath Proof Explorer


Theorem 4on

Description: Ordinal 3 is an ordinal number. (Contributed by Mario Carneiro, 5-Jan-2016)

Ref Expression
Assertion 4on 4o ∈ On

Proof

Step Hyp Ref Expression
1 df-4o 4o = suc 3o
2 3on 3o ∈ On
3 2 onsuci suc 3o ∈ On
4 1 3 eqeltri 4o ∈ On