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6p1e7
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7p1e8
Metamath Proof Explorer
Ascii
Structured
Theorem
6p1e7
Description:
6 + 1 = 7.
(Contributed by
Mario Carneiro
, 18-Apr-2015)
Ref
Expression
Assertion
6p1e7
⊢
( 6 + 1 ) = 7
Proof
Step
Hyp
Ref
Expression
1
df-7
⊢
7 = ( 6 + 1 )
2
1
eqcomi
⊢
( 6 + 1 ) = 7